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stellarik [79]
3 years ago
12

What is the product of (3^5) (2^5) (3^4)

Mathematics
2 answers:
expeople1 [14]3 years ago
8 0

Answer:

629856

Step-by-step explanation:

Snowcat [4.5K]3 years ago
4 0
11,337,408

(3^5) = 729 (2^5) = 64 (3^4) = 243

729 x 64 x 243 = 11,337,408
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The expression x−y equals 0.7 if x and y have certain values. Evaluate the following expressions with the same values of x and y
lisov135 [29]

Answer:

-0.7

Step-by-step explanation:

x-y=0.7

You can choose any digits you wish for x and y but the difference must be 0.7. I chose 1.0 and 0.3.

x=1\\y=0.3\\x-y=0.7\\\\y-x=\\0.3-1=\\-0.7

3 0
3 years ago
Which point is the solution to the following system of equations? x2 + y2 = 13 2x - y = 4
Anit [1.1K]
There are two solutions.
.. (3, 2)
.. (0.2, -3.6)

_____
If you're choosing possibilities from a list, trying them in the equations usually gives quick results.

4 0
3 years ago
Read 2 more answers
Sin4u=2sin 2u cos 2u​
yKpoI14uk [10]

Answer:

If you've learnt sin(A+B) = sinAcosB + cosAsinB,

sin(4u)

= sin(2u+2u)

= sin(2u)cos(2u) + cos(2u)sin(2u)

= 2 sin(2u) cos(2u).

4 0
3 years ago
Add and simplify 1/5 + 1/10
aliya0001 [1]

In order to add these fractions we have to make a common denominator.

1/5 can turn into 2/10 Its the same thing. And its easier to solve with.

now lets multiply.

\frac{2}{10} × \frac{1}{10}

Now we add across

2 + 1 = 3

------------  

10 + 10 = 10 ( When adding fractions like these the denominator stays the same)

So your answer is...

\frac{3}{10}

Good Luck! :)

7 0
3 years ago
The equation r(t)= (2t)i + (2t-16t^2)j is the position of a particle in space at time t. Find the angle between the velocity and
ankoles [38]

Answer:

The answer is 135 degrees.

Step-by-step explanation:

As we are given the position. If we take the <u>derivative</u>, we get the velocity vector. If we take the <u>derivative</u> again, we find the acceleration vector of the particle.

r(t)=(2t)i+(2t-16t^{2})j

V(t)=2i+(2-32t)j

a(t)=-32j

At time t=0;

v(t)=2i+2j

a(t)=-32j

As i attach in the picture the angle between the velocity and acceleration vector is (45+90)=135 degrees

4 0
4 years ago
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