what is the algebraic equation product of 3 and a squared number is twice the sum of the number and 4

1 answer:

6 0

Let n = number

" product of 3 and a squared number" translates to 3n²

"sum of the number and 4" translates to n + 4

The word "is" becomes your equals sign.

3n² = n + 4 is your equation.

You might be interested in

Please help! will mark brainliest

marin [14]

The correct answer is D.

x= -4 and y=2

left 4 up 2

7 0

3 years ago

What is 2+2 then take away 1

laiz [17]

Answer:

Step-by-step explanation:

2 + 2 = 4

4 - 1 = 3

4 0

3 years ago

Read 2 more answers

If F(x)=4x-1 and g(x)=x^2+7, what is g(f(x))

VashaNatasha [74]

Answer

$g(f(x)) = = 16 {x}^{2} - 8x + 8$

step by step Explanation

The functions given are

$f (x)= 4x- 1$

$g(x)= {x}^{2} + 7$

We want to find:

$g(f (x))= g( 4x- 1)$

This implies that

$g(f (x))= ( (4x- 1)^{2} + 7)$

Let us now simplify

$( {a - b)}^{2} = {a}^{2} -2ab + {b}^{2}$

This implies that

$( (4x- 1)^{2} + 7) =( {(4x)}^{2} - 2(4x) \times 1 + 1$

Combine the terms to get,

$= 16 {x}^{2} - 8x + 1 + 7$

$= 16 {x}^{2} - 8x + 8$