Well, since it asks for an estimation, let's make a rough guess.
Let's round 24% to 25%.
25% is 1/4 of 60.
60 divided by 4 equals to 15.
Estimate will be 15.
With this problem, subtract 7 from both sides to get
17< y
So any number that is greater than 17 is a value that would make it true....19, 24, 35, 100, 39,1028
1 meter = 3.2808399 feet
<span>810m * 3.2808399 ft/m </span>
<span>2657.48 feet </span>
<span>2657.48/5.4 </span>
<span>492.12592593 </span>
<span>Scale </span>
<span>1:492 </span>
Answer:
-1
Step-by-step explanation:
-9a<u>(-16+3)</u>=4a ; solve for whole numbers first.
-9a-(13)=4a ; A negative 16 plus a positive 3 is 13.
-9a-4a=13 ; Switch 13 and 4a to make it easier to solve.
-13a=13 ; Now divide each side by -13.
a=-1
Answer:
7088 m²
Step-by-step explanation:
The area of the half-cylinder is half the area of a cylinder with the same dimensions. This half-cylinder has a radius of 0.3 m and a length of 0.8 m, so its area is ...
A = πr(r +l) = π(0.3 m)(0.3 m+0.8 m) = 0.33π m² ≈ 1.0362 m²
The area of the bottom part of the box is the sum of its lateral area and its base area.
lateral area = Ph = (2(0.6m +0.8m))(0.75 m) = 2.1 m²
base area = lw = (0.8 m)(0.6 m) = 0.48 m²
The total area is then ...
total area = half-cylinder area + lateral area + base area
= 1.0362 m² +2.1 m² +0.48 m²
= 3.6162 m²
__
The area for 1960 mailboxes will be 1960 times this area, or ...
area for week's production = 1960 × 3.6162 m² = 7087.752 m²
It will take about 7088 square meters of aluminum to make these mailboxes.