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3 years ago

What is the minimum volume of hot air needed to lift a hot air balloon carrying 800kg

Mathematics

1 answer:

nevsk [136]3 years ago

3 0

Answer:

The minimum volume of hot air needed to lift a hot air balloon carrying 800kg

Is 653.1m³

Step-by-step explanation:

This problem bothers on the density of materials in this problem air

Given data

Volume of air V=?

Mass of air m= 800kg

From tables the density of air is

ρ =1.225 kg/m3

Now to solve for the volume we have

ρ=m/v

v=m/ρ

v=800/1.225

Volume v = 653.1m³

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TiliK225 [7]

The answers are

1: False
2: True
3: True
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4 0

2 years ago

Find the value of x.

tatiyna

Answer:

x = 19

Step-by-step explanation:

(5x+4)+(x-2)+(3x+7) = 180

5x+4+x-2+3x+7 = 180

9x+9 = 180

9x = 171

x = 171/9

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4 0

2 years ago

Read 2 more answers

Maddie bought 3 2/3 yards of satin ribbon at the craft store. She wanted to make hair bows for the cheer squad. Each bow require

kotegsom [21]

Answer:

Step-by-step explanation:

Given that:

Total yards of satin bought by Maddie = $3\frac{2}{3}$ yards

Number of yards required make one ribbon = $\frac{2}{3}$ yards

To find:

Number of complete bows that can be made ?

Solution:

First of all, let us learn about converting the mixed fraction to fractional form.

Formula:

$a\dfrac{b}{c} = \dfrac{a\times c+b}{c}$

Therefore, total yards of satin bought by Maddie can be written in fractional form as:

$3\dfrac{2}{3} = \dfrac{3\times 3+2}{3} = \dfrac{11}{3}$

One hair bow requires $\frac{2}{3}$ yards of ribbon.

Number of hair bows that can be made, can be found by dividing the total ribbon length by ribbon required for making one hair bow.

Answer is:

$\dfrac{\frac{11}{3}}{\frac{2}{3}}\\\Rightarrow \dfrac{11\times 3}{2\times 3}\\\approx 4$

4 hair bows can be made.

4 0

2 years ago

an article when sold at a profit of 5% yields rupees 50 more than when sold at a loss of 5% what was the cost price of the artic

ziro4ka [17]

I'm going to assume that the question should say “at a profit of 5%”.

Restate question in the form of a equation.

Let C = the cost price of the item.

C + 0.705 C = C - 0.05 C + Rs 50

0.05 C = - 0.05 C + Rs 50

0.10 C = Rs 50

C = Rs 500

The cost price of the item is Rs 500

I hope this help you

6 0

3 years ago

4. Jose and Camden both worked hard over the summer. Together, they earned a total of $310. Jose earned $40 more than Camden. Ho

Anni [7]

Easy divide the numbers 310 and 40 like this
310÷40
ANSWER
7.75

6 0

3 years ago