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Alina [70]
3 years ago
15

Someone can you please help

Mathematics
2 answers:
Ainat [17]3 years ago
8 0
Put each number where Y should be (so 24/3 or 39/3) then simplify. If it is less than or equal to 12 than it satisfies the equation. A. Yes B. No C. Yes and D. Yes
Yuri [45]3 years ago
6 0
A) yes
B) No
C) Yes
D) Yes
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A rhombus can always be classified as which of the following?
ollegr [7]

Answer:

square

rectangle

quadrilateral

Step-by-step explanation:

Sides are all equal

3 0
2 years ago
Simplify:<br> 49 - 4 x 49 ÷ 7<br><br><br> 21<br> 34<br> 36
enot [183]

Answer:

21

Step-by-step explanation:

49 - 4 x 49 / 7 =

49 - 196 / 7 =

49 - 28 =

21

<em>Hope that helps!</em>

5 0
2 years ago
Read 2 more answers
The Big Telescope Company sells circular mirrors. Their largest mirrors have radii of 5 meters and their smallest mirrors have r
pogonyaev

Answer: 1:5

Step-by-step explanation:

Given: The cost of every mirror is proportional to the cube of the mirror's radius.

i.e. \dfrac{\text{Cost of smallest mirror}}{\text{Cost of largest mirror}}=\dfrac{(\text{radii of smallest mirror}^3)}{\text{(radii of largest mirror)}^3}

Their largest mirrors have radii of 5 meters and their smallest mirrors have radii of 1 meter.

Then,

\dfrac{\text{Cost of smallest mirror}}{\text{Cost of  largest mirror}}=\dfrac{1^3}{(5)^3}=\dfrac{1}{125}

The ratio of the total cost of 25 of the company's smallest mirrors to the cost of one of the company's largest mirrors will be:

\dfrac{\text{Cost of 25 smallest mirror}}{\text{Cost of largest mirror}}=\dfrac{25\times 1}{125}=\dfrac{1}{5}

Hence, the ratio of the total cost of 25 of the company's smallest mirrors to the cost of one of the company's largest mirrors = 1:5 .

5 0
3 years ago
12m by 7m what is the area
Sergio039 [100]

Answer:

multiply 12*7

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
HELP PLEASE PYTHAGOREAN THEOREM
juin [17]
Your answer is 13.8 or 14

A^2 + B^2 = C^2
7^2 + 12^2 =C^2
49 + 144 = 193
193=13.8 (Square root 193)
C^2 is 13.8 or 14
5 0
2 years ago
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