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Harlamova29_29 [7]
3 years ago
14

Picture available : what percent PLEASE HELP: 10 points

Mathematics
2 answers:
jekas [21]3 years ago
7 0
D is the answer for the question

Charra [1.4K]3 years ago
4 0
D. 36.1% is the answer
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Multiplying Binomials
ch4aika [34]

Answer:

Concept: Binomial Multiplication

  1. (x-1)(x-9)
  2. x^2-9x-x+9
  3. x^2-10x+9

5 0
3 years ago
Find the product of all real values of r for which 1/2x=r-x/7
Dahasolnce [82]

Answer:

r = \±\sqrt{14

Product = -14

Step-by-step explanation:

Given

\frac{1}{2x} = \frac{r - x}{7}

Required

Find all product of real values that satisfy the equation

\frac{1}{2x} = \frac{r - x}{7}

Cross multiply:

2x(r - x) = 7 * 1

2xr - 2x^2 = 7

Subtract 7 from both sides

2xr - 2x^2 -7= 7 -7

2xr - 2x^2 -7= 0

Reorder

- 2x^2+ 2xr  -7= 0

Multiply through by -1

2x^2 - 2xr +7= 0

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

b^2 - 4ac = 0

For a quadratic equation

ax^2 + bx + c = 0

By comparison with 2x^2 - 2xr +7= 0

a = 2

b = -2r

c =7

Substitute these values in b^2 - 4ac = 0

(-2r)^2 - 4 * 2 * 7 = 0

4r^2 - 56 = 0

Add 56 to both sides

4r^2 - 56 + 56= 0 + 56

4r^2 = 56

Divide through by 4

r^2 = 14

Take square roots

\sqrt{r^2} = \±\sqrt{14

r = \±\sqrt{14

Hence, the possible values of r are:

\sqrt{14 or -\sqrt{14

and the product is:

Product = \sqrt{14} * -\sqrt{14}

Product = -14

8 0
3 years ago
What are the coordinate of the vertices of A’B’C after each movement
yuradex [85]
Do you have a picture or sum?
7 0
3 years ago
3/4 divided by 12 as a fraction
Leona [35]

Answer: the answer  is 3/48

8 0
2 years ago
PLZ I NEED HELP
Natasha2012 [34]

Answer:

False

Step-by-step explanation:

10 – [50 ÷ (-2 x 25) -7] x 22 = -18

10 - (50 ÷ (-50)-7) x 22= -18

10 - (-1 - 7) x 22= -18

10 - (-8) x 22 = -18

10 + 8 x 22 = -18

10+176=-18

186=-18

False

6 0
3 years ago
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