System A:
6x + y = 2
-x - y = -3
System B:
2x - 3y = -10
-x-y = -3
Solve:
System A:
6x + y = 2
y = 2 - 6x
-x - (2-6x) = -3
-x - 2 + 6x = -3
5x = -3 + 2
5x = -1
x = -1/5
y = 2 - 6(-1/5)
y = 2 + 6/5
y = 2 + 1.2
y = 3.2 System A: x = -1/5 or -0.2 ; y = 3 1/5 or 3.2
System B:
2x - 3y = -10
2x = -10 + 3y
x = -5 + 1.5y
-x - y = -3
-(-5 + 1.5y) -y = -3
5 - 1.5y - y = -3
-2.5y = -3 - 5
-2.5y = -8
y = 3.2
x = -5 + 1.5(3.2)
x = -5 + 4.8
x = -0.2 System B: x = -0.2 ; y = 3.2
<span>B) They will have the same solution because the first equations of both the systems have the same graph.</span>
where's the rest of question so I can help?
Answer:
B E F G
Step-by-step explanation:
Polygons are 2 dimensional shapes with straight edges (no curved edges). The shape needs to be closed up entirely to be a polygon. It cannot have any intersecting line segments
A can't be a polygon because the shape isn't closed up entirely
C can't be a polygon because it is a 3d shape
D can't be a polygon because it has curved edges.
H can't be a polygon because it isn't closed up (there are no line segments).
I can't be a polygon because polygons cannot have intersecting lines
J can't be a polygon because polygons cannot have intersecting lines
I hope this helps! If it does, a rate or brainliest would be much appreciated. :)
Answer:
ummm i don't see anything
Let's call L the width of the rectangle and W its width. The area of the rectangle is the product between the length and the width, and we are also told that the area is 300 square meters, so we can write

Moreover, we know that the length is 5 meters longer than the width:

We have a system of 2 equations in 2 unknown variables, L and W. If we substitute the second equation into the first one, we get


which has two solutions: W=-20 and W=15. We can discard the negative solution since it does not have physical meaning, and now we can substitute the value of W into the second equation to find L:

<span>Therefore, the rectangle has width 15 meters and length 20 meters.</span>