Question

Construct the graph of the equation y=kx if it is known that the point B belongs to the graph. The graph of which of these two equations goes through point M(−10, 15)?
B(2, −3)
B(3 1/3, -2)
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Answer 1

Answer:

The graph with B(2,-3) i.e) y=$\frac{-3}{2}$ x goes through the point M(-10,15).

Step-by-step explanation:

Consider M(-10,15) and given that equation is y = kx.

Now, substitute M(-10,15) in the equation

⇒ 15 = k × -10

⇒ k = $\frac{15}{-10}$ = $\frac{-3}{2}$

⇒ y = $\frac{-3}{2}$ x

Now, check with the given points B(2,-3) and B($3\frac{1}{3}$ , -2)

1) B(2,-3)

y = $\frac{-3}{2}$ x

⇒(-3) = $\frac{-3}{2}$ × 2

⇒ -3 = -3 ⇒ LHS = RHS

⇒ B(2,-3) is the required point.

2) for b($3\frac{1}{3}$ , -2)

LHS ≠ RHS.

So,The graph with B(2,-3) i.e) y=$\frac{-3}{2}$ x goes through the point M(-10,15).