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velikii [3]
3 years ago
6

a statue on honor Benjamin Franklin will be placed outside the entrance to the Liberty Bell Exhibit Hall in Philadelphia the des

igners that is the side that is smaller similar version will be placed on a table inside the building the dimensions of the life-size statue will be four times those of the smaller statue. planners expect to need 1.5 pints of paint to coat the small statue they also know that the small statue will weight 14 pounds. how much paint will be needed to paint the life sized statue ​
Mathematics
1 answer:
larisa86 [58]3 years ago
6 0

Answer:

Part a) The paint needed will be 24\ pints

Part b) The weight of the life sized statue  is 896\ lb

Step-by-step explanation:

step 1

we know that

If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared

Let

z----> the scale factor

x----> surface area of the life sized statue

y----> surface area of the smaller statue

z^{2}=\frac{x}{y}

we have

z=4

substitute

4^{2}=\frac{x}{y}

x=16y

The surface area of the life sized statue  is 16 times the surface area of the smaller statue

therefore

The paint needed will be

16(1.5)=24\ pints

step 2

Find the weight of the life sized statue

we know that

If two figures are similar, then the ratio of its weights (or volumes) is equal to the scale factor elevated to the cube

Let

z----> the scale factor

x----> weight of the life sized statue

y----> weight of the smaller statue

z^{3}=\frac{x}{y}

we have

z=4

y=14\ lb

substitute

4^{3}=\frac{x}{14}

x=64(14)=896\ lb

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I don’t really get this question so if anyone knows it please help
Mars2501 [29]

Answer:

116.82\:\text{square inches}

Step-by-step explanation:

The window consists of a large square and 4 smaller triangles on the outside. The side length of this square is marked as 10, and therefore the area of this square is 10^2=100\:\mathrm{in^2}.

The area of a triangle is given by \frac{1}{2}\cdot b\cdot h. Since the problem states that the overlapping squares are congruent, both legs of the triangle will be 2.9 and intersect at a 90^{\circ} angle.

Thus, the sum of all four triangles is \frac{1}{2}\cdot 2.9\cdot 2.9\cdot 4=16.82\:\mathrm{in^2}.

Therefore, the area of the window is:

100+16.82=\boxed{116.82\:\mathrm{in^2}}

3 0
3 years ago
Use this equation to find dy/dx. 3y cos x = x2 + y2
Art [367]
Given: 3y cos x = x² + y²

Define y' =  \frac{dy}{dx}

Then by implicit differentiation, obtain
3y' cos(x) - 3y sin(x) = 2x + 2y y'
y' [3 cos(x) - 2y] = 2x + 3y sinx)

Answer:
\frac{dy}{dx} =  \frac{2x+3y \, sin(x)}{3cos(x)-2y}
5 0
3 years ago
Lacy draws a diamond from a standard deck of 52 cards. Without replacing the first card, she then proceeds to draw a second card
Viktor [21]

Answer:

a) i) No

ii) Probability of drawing a diamond and then spade without replacement is 0.0637.

b) i) Yes

ii) Probability of drawing a diamond and then spade with replacement is 0.0625

Step-by-step explanation:

Part a) Without replacement:

i) Are these events independent?

No, because the both events are dependent. because a card taken out of the deck is not replaced back before taking out the other card so the chances of event occur change.

ii) Determine the probability of drawing a diamond and then a spade without replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after taking diamond = 52 -1 =51

Spades = 13

Probability of drawing a spade  = 13/51

Probability of drawing a diamond and then spade = 13/52 * 13/51

= 169/2652

=0.0637

So, Probability of drawing a diamond and then spade without replacement  is 0.0637

Part b) With replacements

i) Are these events independent?

Input Yes or No:

Yes, these events are independent because a card taken out of the deck is replaced back before taking out the other card so the chances of event occur doesn't change.

ii) Determine the probability of drawing a diamond and then a spade with replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after replacing diamond = 52

Spades = 13

Probability of drawing a spade  = 13/52

Probability of drawing a diamond and then spade = 13/52 * 13/52

= 169/2704

=0.0625

So, Probability of drawing a diamond and then spade with replacement is 0.0625

7 0
3 years ago
Calculate the area of the shaded region. Use 3.14 for pi; round to the nearest tenth, if needed. HELP PLSSS I HAVE TO GET THIS D
icang [17]

Answer:

87.48

Step-by-step explanation:

First find the area of the square

12^2=144

find area of the 2 circles

9*3.14

but theres 2

18*3.14=56.52

144-56.52=87.48

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3 years ago
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ankoles [38]
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