Answer:
Part a) The paint needed will be 
Part b) The weight of the life sized statue is 
Step-by-step explanation:
step 1
we know that
If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared
Let
z----> the scale factor
x----> surface area of the life sized statue
y----> surface area of the smaller statue
we have
substitute

The surface area of the life sized statue is 16 times the surface area of the smaller statue
therefore
The paint needed will be

step 2
Find the weight of the life sized statue
we know that
If two figures are similar, then the ratio of its weights (or volumes) is equal to the scale factor elevated to the cube
Let
z----> the scale factor
x----> weight of the life sized statue
y----> weight of the smaller statue
we have
substitute
