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zmey [24]
3 years ago
11

{(24p – 66) = 3p + 43

Mathematics
1 answer:
Alenkinab [10]3 years ago
5 0

\text {Hello! Let's Solve this Equation!}

\text {\underline {The First Step is to Subtract 3p}}

\text {24p-66-3p=3p+43-3p}

\text {Your New Problem Is: 21p-66=43}

\text {\underline {The Next Step Is to Add 66}}

\text {21p-66+66=43+66}

\text {Your New Problem Is: 21p=109}

\text {\underline {The Final Step is to Divide 21}}

\text {21p/21=109/21}

\text {Your Answer Would Be:}

\fbox {p=109/21}

\text {Best of Luck!}

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El área superficial total de los veinte tarugos es mayor que el área superficial cubierta por el pegamento.

<h3>Como determinar si la superficie cubierta por el pegamento es suficiente</h3>

En esta pregunta debemos calcular el área superficial total de los tarugos (A_{s}), en milímetros cuadrados, y comparar el resultado con la cifra afirmada por Eduardo. El área superficial total es:

A_{s} = 20\cdot \pi\cdot (5\,mm)^{2}\cdot (80\,mm)

A_{s} \approx 125663.706\,mm^{2 }

En consecuencia, el área superficial total de los veinte tarugos es mayor que el área superficial cubierta por el pegamento. Francisca tiene la razón. \blacksquare

<h3>Observación</h3>

El enunciado omite las dimensiones <em>geométricas</em> de cada tarugo (5 milímetros de radio y 80 milímetros de longitud).

Para aprender más sobre áreas, invitamos cordialmente a ver esta pregunta verificada: brainly.com/question/391394

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hope this helps

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