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melomori [17]
3 years ago
11

A conference room is in the shape of a rectangle. Its floor has a length of (x − 4) meters and a width of (3x − 1) meters. The e

xpression below represents the area of the floor of the room in square meters: (x − 4)(3x − 1) Which of the following simplified expressions represents the area of the floor of the conference room in square meters?
Mathematics
2 answers:
Kamila [148]3 years ago
6 0
You have to foil. Times the first two: x(3x). Then times the outer two: x(-1). Then times the inner two: -4(3x). Finally, times the last two: -4(-1). Your equation would be 3x squared - 1x - 12x + 4. Therefore, the simplified answer is 3x^2 (3x to the second power) - 13x + 4.
Norma-Jean [14]3 years ago
4 0

Answer:

Simplified expressions which represents the area of the floor of the conference room in square meters is:

3x²-13x+4

Step-by-step explanation:

A conference room is in the shape of a rectangle.

Its floor has a length of (x − 4) meters and a width of (3x − 1) meters.

we know that Area of rectangle=Length×Breath

Area of floor of the room=(x-4)(3x-1)

(x-4)(3x-1)=x(3x-1)-4(3x-1) (Distributive property)

               = 3x²-x-12x+4   (Distributive property)

              = 3x²-13x+4   (On combining the like terms)

Hence, simplified expressions which represents the area of the floor of the conference room in square meters is:

3x²-13x+4

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An electronics company produces​ transistors, resistors, and computer chips. Each transistor requires 3 units of​ copper, 2 unit
Gala2k [10]

Answer:

475 transistors, 25 resistors and 50 computer chips can be produced.

Step-by-step explanation:

Let us consider, p = Number of transistors.

                           q = Number of resistors.

                            r = Number of computer chips.

The following three linear equations according to question,

3\times p + 3\times q + 2\times r = 1600\\2\times p + 1\times q + 1\times r = 1025\\1\times p + 2\times q + 2\times r = 625

The matrix form of any system, Ax = B

Where, A = Coefficient matrix

            B = Constant vector

            x = Variable vector

A = \left[\begin{array}{ccc}3&3&2\\2&1&1\\1&2&2\end{array}\right], x = \left[\begin{array}{ccc}p\\q\\r\end{array}\right], B = \left[\begin{array}{ccc}1600\\1025\\625\end{array}\right]

The inverse matrix, A^{-1} can be found by using the following formula,

           A^{-1} = \frac{1}{det A}\times (C_{A}) ^{T}

Where, det A = Determinant of matrix A.

                 C_{A} = Matrix of cofactors of A

Now, applying this formula to find A^{-1};

det A = \left[\begin{array}{ccc}3&3&2\\2&1&1\\1&2&2\end{array}\right] = 3\times(2-2)-3\times(4-1)+2\times(4-1) = -3

Here, det A\neq 0, thus the matrix is invertible.

C_{A} = \left[\begin{array}{ccc}(2-2)&-(4-1)&(4-1)\\-(6-4)&(6-2)&-(6-3)\\(3-2)&-(3-4)&(3-6)\end{array}\right] = \left[\begin{array}{ccc}0&-3&3\\-2&4&-3\\1&1&-3\end{array}\right] \\(C_{A}) ^{T} = \left[\begin{array}{ccc}0&-3&3\\-2&4&-3\\1&1&-3\end{array}\right] ^{T} = \left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right]

A^{-1} = \frac{1}{-3}\times\left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right]  \\ So, x= \frac{1}{-3} \left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right]\times\left[\begin{array}{ccc}1600\\1025\\625\end{array}\right]= \frac{1}{-3} \left[\begin{array}{ccc}-1425\\-75\\-150\end{array}\right] = \left[\begin{array}{ccc}475\\25\\50\end{array}\right]

So, p = 475, q = 25, r = 50.      

7 0
3 years ago
Carter's account has gone into overdraft. His balance is $-43.3. To get back to a positive balance, he plans to deposit money at
Dvinal [7]

Answer:

125.05

Step-by-step explanation:

Used a calculator lol

3 0
2 years ago
Please help me answer this​
butalik [34]

Answer:

1) 1:2          2) 3

3) 1:8         4) 2:7

5) 1:4         6) 3:7

7) 2:5         8) 3:11

9) 2:7         10) 4:7

11) 8:9        12) 7:11

13) 1:2        14) 3

15) 26:27   16) 1:40

17) 1:10       18) 1:100

19) 1000    20) 10

Step-by-step explanation:

4 0
3 years ago
Let f be the function that determines the area of a circle (in square cm) that has a radius of r cm. That is, f ( r ) represents
Zepler [3.9K]

Answer:

(a)f(4) square cm.

(b)f(10.91)-f(10.9) Square centimeter.

Step-by-step explanation:

f(r)=the area of a circle (in square cm) that has a radius of r cm.

(a)Area (in square cm) of a circle whose radius is 4 cm.

Since r=4cm

Area of the circle = f(4) square cm.

(b) When the radius of the increases from 10.9 to 10.91 cm.

  • Area of the circle with a radius of 10.91 = f(10.91) square cm.
  • Area of the circle with a radius of 10.9 = f(10.9) square cm.

Change in the Area = f(10.91)-f(10.9) Square centimeter.

4 0
4 years ago
Y and x have proportional relationship and y=15 when x=3 what is the value of x when y=4 ??????
GrogVix [38]
The answer would be x=-14
3 0
4 years ago
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