The ratios as fractions are 6/8 and 9/11.
Since they are not compare because they have different denominators you must find the Least Common Multiple of the two fractions.
Since 8 and 11 both can go into 88, we can use that as our denominator.
6/8 times 11/11 equals 66/88 and 9/11 times 8/8 equals 72/88.
66/88 is less than 72/88.
Therefor, Mix B is the reddest mixture.
Hope this helped!! :)
Answer:
x = 73.4°
Step-by-step explanation:
sin x° = 23/24
sin x° = 0.9583
x = 73.4°
Answer:
Jenny cycles the grand distance of 29 and one third of a mile.
Step-by-step explanation:
I want to answer this using fractions and without multiplying by an awkward recurring decimal.
Cycling 11 miles in 45 minutes and continuing at the same speed means she will go 22 miles in 90 minutes
To scale up 90 mins to the required 120 mins (2 hours) multiply by 4/3.
22 x (4/3) = 88/3
Jenny will travel 88/3 miles in 2 hours.
Not happy with top heavy fractions?
Let's round up 88/3 to 90/3 by adding 2/3.
90/3 = 30 and to get back to the answer we just take away the two thirds we added when rounding up.
Jenny cycles the grand distance of 29 and one third of a mile.
I think that is the correct answer.
Given that a person's normal body temperature is 98.6 ° F, and according to physicians, a person's body temperature should not be more than 0.5 ° F from the normal temperature, to determine how you could use an absolute value inequality to represent the temperatures that fall outside of normal range, the following logical-mathematical reasoning must be carried out:
As long as the normal temperature is 98.6 ° F, and its variation should not be greater than 0.5 ° F in its increase or decrease, it is correct to say that the range of normal body temperatures is equal to 98.6 - 0.5 to 98.6 + 0.5, that is, it has a variability that goes from 98.1 ° F to 99.1 ° F.
Thus, the absolute value inequality of 0.5 (both subtracting and adding) determines the limits of the temperature parameter considered normal.
Learn more in brainly.com/question/4688732
Answer: The vectors are linearly dependent.
The solution is in the attachment
