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Dmitry_Shevchenko [17]
3 years ago
10

What is the domain of f(x) = 3x – 2?

Mathematics
2 answers:
lesantik [10]3 years ago
8 0

Answer:

{x | x is a real number}

Step-by-step explanation:

Given function is f\left(x\right)=3x-2

Now we need to find out what is the domain of the given function f\left(x\right)=3x-2 and match with the correct choice from the given choices.

{x | x > 0}

{x | x < 0}

{x | x = 0}

{x | x is a real number}

We can see that f\left(x\right)=3x-2 is in the form of y=mx+b that means it is an equation of line. and we know that a line can go in both directions withut any break. Hence domain is all real numbers.

So the correct choice is {x | x is a real number}

Elis [28]3 years ago
3 0

Answer: las option.

Step-by-step explanation:

The equation of the line in slope-intercept form is:

y=mx+b

Where m is the slope of the line and b is the y-intercept.

Then function given in the problem has the form:

f(x)=3x-2

Where:

m=3

b=-2

Therefore, it is a linear function.

By definition, the domain of the  linear functions that are not bounded, is all the Real numbers.

Therefore, the answer is:

<em> {x | x is a real number}</em>

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Given:

In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and m\angle BCD=30^\circ.

To find:

The m\angle AOB.

Solution:

If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.

We have, DC is parallel to BA and BC is the transversal line.

\angle OBA\cong \angle BCD        [Alternate interior angles]

m\angle OBA=m\angle BCD

m\angle OBA=30^\circ

In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.

The base angles of an isosceles triangle are congruent. So,

\angle OAB\cong \angle OBA      [Base angles of an isosceles triangle]

m\angle OAB=m\angle OBA

m\angle OAB=30^\circ

Using the angle sum property in triangle AOB, we get

m\angle OAB+m\angle OBA+m\angle AOB=180^\circ

30^\circ+30^\circ+m\angle AOB=180^\circ

60^\circ+m\angle AOB=180^\circ

m\angle AOB=180^\circ-60^\circ

m\angle AOB=120^\circ

Hence, the measure of angle AOB is 120 degrees.

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2 years ago
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kirza4 [7]

93+(68+7)

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Answer:

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Step-by-step explanation:

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