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3 years ago

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A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 428428 gram setting.

It is believed that the machine is underfilling or overfilling the bags. A 7171 bag sample had a mean of 433433 grams with a variance of 441441. Assume the population is normally distributed. A level of significance of 0.010.01 will be used. Specify the type of hypothesis test.

1 answer:

Lunna [17]3 years ago

3 0

Answer:

z-test

Step-by-step explanation:

-A z-test is a test used to determine the difference in two population means of known variances.

-The sample size has to be large enough, $n\geq 30$ (n=71).

-And, the population must follow a normal distribution.

-Since our sample meets all the above conditions, the hypothesis test used is a z-test

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Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos

crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c) $P(X = 2)$ is unusual, $P(X = 0)$ is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A number of sucesses $x$ is considered unusually low if $P(X \leq x) \leq 0.05$ and unusually high if $P(X \geq x) \geq 0.05$

In this problem, we have that:

Two cans are randomly chosen, so $n = 2$

Two out of 18 cans are filled with diet coke, so $\pi = \frac{2}{18} = 0.11$

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121$

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921$

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that $P(X = 2)$ is unusual, since $P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05$

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958$

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0

3 years ago

Help plz :((<br> I'll give brainliest

tamaranim1 [39]

For A. the muddy water will slowly begin to decrease because it's been left out in the sun, some of the water will begin to evaporate.

(I don't know about B, or C, but I tried my best on A.)

Make sure to put in your own words. :)

7 0

3 years ago

Point m is located at 4,-2 what is located 2 units for point m

eimsori [14]

Answer:

None

Step-by-step explanation:

Given

$m = (4,-2)$

Required

Point 2 units from m

There are 4 possible points 2 units from m and they are:

$m' = (4+2,-2) = (6,-2)$

$m" = (4,-2+2) = (4,0)$

$m'''= (4-2,-2) = (2,-2)$

$m'''' = (4,-2-2) = (4,-4)$

From the graph, we have:

$A = (4,2)$

$B = (-4,2)$

$C = (2,-3)$

None of the points is 2 units from m

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2 years ago

Where were MOST of France's colonies located in Africa?

PtichkaEL [24]

A in the west africa

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2 years ago

Triangles ABC and DFG are similar.

garik1379 [7]

Answer:

5DG=156 I think this is but I am not sure bro

4 0

2 years ago

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