Find the area, and round to the nearest tenth

f the principal is $350 and the interest rate is 3 percent, what is the simple interest earned in one year?

damaskus [11]

Answer:

$10.50

Step-by-step explanation:

The formula is Balance= Principle (starting amount) x Time x Interest rate. 350 x .03 x 1 is $10.50.

8 0

3 years ago

Guys help plz and I will give brainliest

rewona [7]

Answer:

add 12 for all sides I think

Step-by-step explanation:

but if 12 yd is on both sides you must add 12+12 and the after getting the answer add then with 12+12

4 0

3 years ago

Chris plans to buy a car that depreciates in value at a rate of 10% per year. If the car initially costs $32,000. How much will

VLD [36.1K]

The car would be worth $16,000 after 5 years.

5 0

3 years ago

According to the table, Tasha initially had blank dollars before purchasing songs, and the cost of each song was blank dollars

melomori [17]

Total money before purchasing = $30

Cost of each song = $1.20

Solution:

According to the table,

No. of songs Amount

2 27.60

3 26.40

4 25.20

Difference between amount she have after bought 3 songs to 2 songs:

27.60 – 26.40 = 1.20

Difference between amount she have after bought 4 songs to 3 songs:

26.40 – 25.20 = 1.20

So, the cost of each song = $1.20

Amount of money she had after purchasing one song = $27.60 + $1.20

= $28.80

Tasha initially had before purchasing songs = $28.80 + $1.20

= $30

Hence Tasha initially had $30 before purchasing songs and the cost of each song was $1.20.

5 0

3 years ago

The College Boards, which are administered each year to many thousands of high school students, are scored so as to yield a mean

Marysya12 [62]

Answer:

a) 15.87% of the scores are expected to be greater than 600.

b) 2.28% of the scores are expected to be greater than 700.

c) 30.85% of the scores are expected to be less than 450.

d) 53.28% of the scores are expected to be between 450 and 600.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 500, \sigma = 100$

a. Greater than 600

This is 1 subtracted by the pvalue of Z when X = 600. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{600 - 500}{100}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413.

1 - 0.8413 = 0.1587

15.87% of the scores are expected to be greater than 600.

b. Greater than 700

This is 1 subtracted by the pvalue of Z when X = 700. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{700 - 500}{100}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% of the scores are expected to be greater than 700.

c. Less than 450

Pvalue of Z when X = 450. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{450 - 500}{100}$

$Z = -0.5$

$Z = -0.5$ has a pvalue of 0.3085.

30.85% of the scores are expected to be less than 450.

d. Between 450 and 600

pvalue of Z when X = 600 subtracted by the pvalue of Z when X = 450. So

X = 600

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{600 - 500}{100}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413.

X = 450

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{450 - 500}{100}$

$Z = -0.5$

$Z = -0.5$ has a pvalue of 0.3085.

0.8413 - 0.3085 = 0.5328

53.28% of the scores are expected to be between 450 and 600.

6 0

2 years ago