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Ket [755]
3 years ago
5

1 - 2x + 3y for x = -2 and y= -5

Mathematics
2 answers:
Kay [80]3 years ago
6 0

Answer:

All you need to do is plug the values and then simplify!

\large{ \tt{ - 2x + 3y}}

  • Plug the value of x and y :

\longrightarrow \: \large{ \tt{ - 2 \times ( - 2) + 3 \times ( - 5)}}

  • When negative integer is multiplied by negative integers , we get positive integer & when positive integer is multiplied by negative integer , we get negative integer.

\longrightarrow \large{ \tt4 + ( - 15){}}

\longrightarrow \large{ \tt{4 - 15}}

\longrightarrow{ \large{  \boxed{ \tt{ - 11}}}}

  • Hence , Our simplified answer is -11 .

~Hope this helps! *Let me know if you have any other queries regarding my answer ! <3

Alekssandra [29.7K]3 years ago
5 0
1-2(-2)+3(-5)
1-(-4)-15
1+4-15
10 is your answer
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3 0
2 years ago
Find the center, vertices, and foci of the ellipse with equation 2x2 + 8y2 = 16.
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4 0
3 years ago
Consider the function below. (If an answer does not exist, enter DNE.) f(x) = x3 − 27x + 3 (a) Find the interval of increase. (E
xxTIMURxx [149]

Answer:

(-∞,-3) and (3,∞)  

Step-by-step explanation:

f(x) = x³ − 27x + 3

1. Find the critical points

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f'(x) = 3x² -27  

(b) Factor the first derivative

f'(x)= 3(x² - 9) = 3(x + 3) (x - 3)

(c) Find the zeros

3(x + 3) (x - 3) = 0

x + 3 = 0      x - 3 = 0

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The critical points are at <em>x = -3</em> and x = 3.

2. Find the local extrema

(a) x = -3

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(b) x = 3

f(x) = x³ − 27x + 3 = 3³ - 27(3) + 3 = 27 - 81 + 3 = -51

The local extrema are at (-3,57) and (3,-51).

3, Identify the local extrema as maxima or minima

Test the first derivative (the slope) over the intervals (-∞, -3), (-3,3), (3,∞)

f'(-4) = 3x² -27 = 3(4)² - 27  = 21

f'(0) = 3(0)² -27 = -27

f'(4) = 3(4)² - 27 = 51

The function is increasing on the intervals (-∞,-3) and (3,∞).

The graph below shows the critical points of your function.

6 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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