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velikii [3]
3 years ago
9

What’s the answer? I don’t understand

Mathematics
1 answer:
pashok25 [27]3 years ago
8 0
The system of equations does not have one solution because the lines will never intersect (last one)
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Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
Which statement is true?
Archy [21]
Your answer is gonna be C
7 0
3 years ago
Write the sum of 18 + 27 as the product of their GCF and another sum <br><br> (PLEASE HELP)
nikdorinn [45]
27
18
----
45

GCF of 45 = 15 
Here is a word document on Greatest Common Factors and how to solve it.

Download docx
4 0
3 years ago
F(x) = x2+3x+2 x2+5x+4 Why is there no zero at x = –1?
dmitriy555 [2]
You could rewrite F(x) as

\dfrac{x^2+3x+2}{x^2+5x+4}=\dfrac{(x+1)(x+2)}{(x+1)(x+4)}

and be tempted to cancel out the factors of x+1. But this cancellation is only valid when x\neq-1.

When x=-1, you end up with the indeterminate form \dfrac00, which is why -1 is not a zero.
7 0
3 years ago
PLEASE HELPPP HELP HELP HELP HELP ASAPPP MATH AHHHHH
Rom4ik [11]

Answer:

66

Step-by-step explanation:

121 - 55 = 66

8 0
3 years ago
Read 2 more answers
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