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Vinvika [58]
3 years ago
7

Give an example of when and why one would use a continuity correction factor?

Mathematics
1 answer:
iris [78.8K]3 years ago
3 0

Answer:

An example of when a continuity correction factor can be used is in finding the number of tails in 50 tosses of a coin within a given range .

and continuity correction factor is used when a continuous probability distribution is used on a discrete probability distribution

Step-by-step explanation:

An example of when a continuity correction factor can be used is in finding the number of tails in 50 tosses of a coin within a given range .

continuity correction factor is used when a continuous probability distribution is used on a discrete probability distribution,  continuity correction factor creates an adjustment on a discrete distribution while using a continuous distribution

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When (1,2) is substituted into the first equation, the equation is true.
The ordered pair (1,2) is a solution to the system of linear equations.
When (1,2) is substituted into the second equation, the equation is true.

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Find the value of x, y, and z in the rhombus below.
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Solution:

<u>It should be noted:</u>

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<u>Thus:</u>

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<u>Finding x:</u>

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<u>Finding y:</u>

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<u>Finding z:</u>

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4 0
2 years ago
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Which of the following is in the solution set of y&lt; 8 x− 3? Select one: (7, 46) (7, 60) (10, 89) (9, 82)
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Answer:

  (7, 46)

Step-by-step explanation:

The offered answer choices have x-values of 7, 9, 10. The corresponding upper limit of y-value is ...

  x=7 : y < 8·7 -3 = 53 . . . . . 46 is in the solution set, 60 is not

  x=9 : y < 8·9 -3 = 69 . . . . 82 is not in the solution set

  x=10 : y < 8·10 -3 = 77 . . . . 89 is not in the solution set

Of the choices offered, only (7, 46) is in the solution set.

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3 years ago
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<h2><u>Given</u><u>:</u><u>-</u></h2>

{ \large{➢ \:  \:  \bf{x =  - 8}}}

<h2><u>Solution</u><u>:</u><u>-</u></h2>

{ \large{➢ \:  \:  \bf{ \dfrac{2y}{3}  = 3 \times  - 8 + 34}}}

{ \large{➢ \:  \:  \bf{ \dfrac{2y}{3}  =  - 24 + 34}}}

{ \large{ \bf{ ➢ \:  \: \cancel{2}y = 3 \times { \cancel{(10)} {} \:  \:  ^{5} }}}}

{ \large{ \therefore{  \bf{y = 15 \:  \: Ans.}}}}

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