Give an example of when and why one would use a continuity correction factor?
1 answer:
You might be interested in
Answer:
The density of the marble is 2,000 kg/m³
Step-by-step explanation:
The given parameters for finding the density of the marble are;
The volume of water in the graduated cylinder, v₁ = 20 ml
The mass of the marble dropped into the graduated cylinder, m = 8 g
The new volume of the cylinder after the 8 g marble is dropped into the cylinder, v₂ = 24 ml
Therefore, the volume of the marble, v = v₂ - v₁
Substituting the known values gives;
The volume of the marble, v = 24 ml - 20 ml = 4 ml
Density, ρ = Mass, m/(Volume, v), the units of density is kg/m³
Therefore, the density of the marble, , is given as follows;
= m/v = (8 g)/(4 ml) = 2 g/ml
1 g/ml = 1 kg/l = 1,000 kg/m³
∴ = 2 kg/l = 2,000 kg/m³.
Answer:
<u>15 students</u> purchase their lunches in the cafeteria.
Step-by-step explanation:
Given:
At eastwood middle school, 25% of the 60 students Mrs. Wade teaches buy their lunches in the cafeteria.
Now, to find the students purchase their lunches in the cafeteria.
Total students = 60.
Percent of students who buy lunches = 25%.
So, to get the number of students who buy their lunches in the cafeteria:
<u><em>25% of 60.</em></u>
Therefore, 15 students purchase their lunches in the cafeteria.