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asambeis [7]
4 years ago
12

How do I solve this? It’s on Khan Academy

Mathematics
1 answer:
Diano4ka-milaya [45]4 years ago
5 0

AC being parallel to RP makes the triangles ABC and RBP similar. This means corresponding sides occur in the same ratio, so that

\dfrac{AC}{RP}=\dfrac{BC}{BP}=\dfrac{AB}{RB}

It's not clear from the picture what it is that you're supposed to find, but from the above relation we have

\dfrac{18}{RP}=\dfrac{BP+10}{BP}=\dfrac{14+7}7

From this it follows that

\dfrac{18}{RP}=\dfrac{21}7=3\implies RP=\dfrac{18}3=6

and

\dfrac{BP+10}{BP}=\dfrac{21}7=3\implies BP+10=3BP\implies2BP=10\implies BP=5

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Answer:

  1. 1
  2. - 9
  3. 13
  4. 15

Step-by-step explanation

- 7(6x-1)+x=36

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  2. => 43x - 7 = 36
  3. => 43x =  36 + 6 = 43
  4. => x = 43 / 43 = 1

- 11-2(8+3p)=7²

  1. => 11 - 16 - 6p = 7^2
  2. => 11 - 16 - 6p = 49
  3. => -5 - 6p = 49
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  5. => p = (54) / (-6) = - 9

-  1/4(5b+11)=19

  1. => (5/4)b +  (11/4) = 19
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- 2/7(4m-18)=12

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3 years ago
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