Answer:
- 6 2/3 qt 80%
- 13 1/3 qt 20%
Step-by-step explanation:
It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.
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We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...
0.80x +0.20(20-x) = 0.40(20)
0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify
x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution
(20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed
The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.
Answer:
x = 46°
Step-by-step explanation:
the opposite angles of a cyclic quadrilateral are supplementary, sum to 180° , then
x + 134° = 180° ( subtract 134° from both sides )
x = 46°
For angles in first quadrant, the reference angle is itself. In second quadrant, the equation would be 180 - x where x is the measure of the angle. In third quadrant, x - 180. Lastly, in the fourth quadrant, the reference angle is 360 - x. From the second set of angles in the given, the reference angles are.
(1) 135 ; RA = 180 - 135 = 45
(2) 240; RA = 240 - 180 = 60
(3) 270; RA = 90 (lies in the y - axis)
(4) 330; RA = 360 - 330 = 30
<span>A: The middle 95% contain between 23.8 and 24.2 oz.(2 SDs under and over the mean)
B: Approximately 68% of boxes have between 23.9 and 24.1 oz of cereal (1 SD under and over the mean)
C: 2.5% of boxes contain more than 24.2, because 95% are within 2 SDs, and that includes lower and higher extremes.
D: 16% of boxes have more than 24.1, because 68% are within 1 SD of the mean, so 32 are left, and that includes lower and higher extremes.</span>
