Solve for the value of n (9n) (8n+8)
1 answer:
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Let us denote the smaller even integer by 
.
Then, the next even integer must be
.
To verify, set as any even number, say 
.
Then, the next even integer must be 2 more than this number, i.e.
.
The sum of these two consecutive even integers can be expressed as:
We are told that this sum divided by four is 189.5, i.e.
Multiplying both sides by 4 will reverse the division:
Subtracting 2 from each side will reverse the addition:
Dividing both sides by 2 will reverse the multiplication:
Therefore, the two consecutive integers must be 378 and 380.
Check this:
Then, the next even integer must be
To verify, set
Then, the next even integer must be 2 more than this number, i.e.
The sum of these two consecutive even integers can be expressed as:
We are told that this sum divided by four is 189.5, i.e.
Multiplying both sides by 4 will reverse the division:
Subtracting 2 from each side will reverse the addition:
Dividing both sides by 2 will reverse the multiplication:
Therefore, the two consecutive integers must be 378 and 380.
Check this: