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lorasvet [3.4K]
3 years ago
13

What must the length of segment AD be for the quadrilateral to be a parallelogram? 8 units 16 units 31 units 62 units

Mathematics
2 answers:
Deffense [45]3 years ago
5 0

Answer:

the answer is C. 31 units

I just did the assignment

Colt1911 [192]3 years ago
4 0

Answer:31

Step-by-step explanation:

I got it right

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This hanger is in balance. There are two labels weight. What is the weight of each circle on grams?
Citrus2011 [14]

Answer:

since there is no image attached I can't see what weight they could be labeled but since the scale is even the weights must be the same number weight

Step-by-step explanation:

hope this helped!

6 0
3 years ago
Richard works at an ice cream shop. Regular cones get two scoops of ice cream; large cones get three scoops. One hot Saturday, R
sasho [114]
There are 16 ounces in one pound, how many scoops are in 10 pounds?

6 0
3 years ago
Help please! Could you explain it too?
Anettt [7]

Answer:

a) not proportional

b) proportional; k = -\frac{3}{5}

Step-by-step explanation:

a) for any proportional equation, the line must pass through the origin. The equation in a) is y = 4x + 1, and the '+1' is the y-intercept. This means that the line does not pass through the origin, so x and y cannot increase by the same amount (i.e. they are not proportional).

Another way to determine this is is to use the y = kx base. If you have an equation that fits that it's likely proportional.

Here, if the equation was only y = 4x then it'd be proportional because u can see that k = 4. This is not the equation though, and the 4x + 1 doesn't fit to the y = kx formula so it can't be proportional.

b) straight away you can see that there's no 'c' term (y = mx + c) which means the y-intercept is 0, so the line passes through the origin. While this does not immediately mean the line is proportional, you can make sure that it is by checking it fits with the y = kx equation.

y = -(3/5)x fits with y = kx, with k being -3/5

3 0
3 years ago
If u=<2,2> then find u•u and determine whether it is a vector or a scalar
Kitty [74]
If ~v = hv1, v2, v3i and ~w = hw1, w2, w3i are vectors and c is a scalar, then (a) c~v = hcv1, cv2, cv3i (b) ~v + ~w = hv1 + w1, v2 + w2, v3 + w3i (c) ~v − ~w = hv1 − w1, v2 − w2, v3 − w3i.
3 0
4 years ago
The equation of a quadratic is =2^2+3−2and after you factorizing 2^2+3−2=0you got x = -2 and x = 1/2 and the curve crosses the y
Lelechka [254]

Given the next quadratic function:

y=2x^2+3x-2

to sketch its graph, first, we need to find its vertex. The x-coordinate of the vertex is found as follows:

x_V=\frac{-b}{2a}

where <em>a</em> and <em>b</em> are the first two coefficients of the quadratic function. Substituting with a = 2 and b = 3, we get:

\begin{gathered} x_V=\frac{-3}{2\cdot2} \\ x_V=-\frac{3}{4}=-0.75 \end{gathered}

The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:

\begin{gathered} y_V=2x^2_V+3x_V-2 \\ y_V=2\cdot(-\frac{3}{4})^2+3\cdot(-\frac{3}{4})-2 \\ y_V=2\cdot\frac{9}{16}+3\cdot(-\frac{3}{4})-2 \\ y_V=\frac{9}{8}-\frac{9}{4}-2 \\ y_V=-\frac{25}{8}=-3.125 \end{gathered}

The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get:

6 0
2 years ago
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