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Blizzard [7]
2 years ago
7

Richard works at an ice cream shop. Regular cones get two scoops of ice cream; large cones get three scoops. One hot Saturday, R

ichard scooped 234 regular cones and 156 large cones. One scoop of ice cream is 3 ounces. A tub of ice cream weighs 10 pounds. How many tubs of ice cream did Richard use to make the cones?
Mathematics
1 answer:
sasho [114]2 years ago
6 0
There are 16 ounces in one pound, how many scoops are in 10 pounds?

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Two people are standing on opposite sides of a hill. Person A makes an angle of elevation of 65° with the top of the hill and pe
8090 [49]

Answer:

Option 3. 71 ft. is the distance between B and top of the hill.

Step-by-step explanation:

Let the height of the hill is h ft and the distance of A from the hill be x ft and distance from B to hill is y.

It is given distance between A and B is 45 ft. ∠BAO = 65° and ∠ABO = 80°.

We have to find the distance of B from the top of the hill.

Now from ΔACO tan 65 = \frac{h}{45-x} = 2.14

h=2.14(45-x)

From ΔBCO tan80 = \frac{h}{x} = 5.67

h = 5.67x

Now h = 5.67x = 2.14(45-x)

5.67x = 96.3 - 2.14x

2.14x + 5.67x = 96.3

7.81x = 96.3

x = 96.3/7.81 = 12.33 ft

Therefore cos80 = \frac{x}{OB}

0.174 = \frac{12.33}{OB}

OB = \frac{12.33}{.174}=70.86=71ft.

Therefore 71 ft is the distance between B and the top of the hill.

3 0
3 years ago
Please help me find limit​
cluponka [151]

9514 1404 393

Answer:

  -13/11

Step-by-step explanation:

Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...

  \displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}

4 0
3 years ago
Can u guys help me please
shusha [124]
Its y=3/4x+3

you can solve it

-3x+4y=12

add 3x both sides

4y=3x+12

divide 4 by both sides

y=3/4x+4
8 0
2 years ago
Read 2 more answers
Please help me with this question!
gavmur [86]
First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway   thus

\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{first sol'n}&11&x&11x\\
\textit{second sol'n}&4&0.55&2.20\\
------&-----&-------&-------\\
mixture&y&0.77&0.77y
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
11+4=y\implies 15=\boxed{y}\\
11x+2.2=0.77y\\
----------\\
11x+2.2=0.77\cdot \boxed{15}
\end{cases}

solve for "x"
6 0
3 years ago
60 students study a language at a school.
mixas84 [53]
  1. The number of girls is 24.
  2. The number of boys that study French is 24.
  3. The numbber of boys that study German is 12.
  4. The number of girls that study French is 16
  5. The number of girls that study German is 8.

<h3>How to fill the frequency tree?</h3>

The number of girls = total number of students - total number of boys

60 - 36  = 24

The number of boys that study French = 2/3 x 36 = 24

The numbber of boys that study German = 36 - 24 = 12

The number of girls that study French = 40 - 24 = 16

The number of girls that study German = 24 - 16 = 8

Please find attached the frequency tree. To learn more about addition, please check: brainly.com/question/349488

#SPJ1

3 0
2 years ago
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