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3 years ago

Help solve this problem 429 × 23

Mathematics

2 answers:

sineoko [7]3 years ago

4 0

The answer is 9 thousand 8 hundred and 67

Nataly [62]3 years ago

3 0

The following operation is your answer:
429 × 23 = 9,867

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Help plz I will give brainliest!!!

posledela

Answer:

width = 6k², length = 5k + 1

Step-by-step explanation:

Given

A = 30k³ + 6k² ← factor out 6k² from each term

= 6k²(5k + 1)

Since area = width × length , then

width = 6k² and length = 5k + 1

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2 years ago

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Answer:

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2 years ago

Find the hypotenuse,c, of the triangle!

Ulleksa [173]

Answer:

Step-by-step explanation

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2 years ago

Find the exact solutions of x2 − 3x − 5 = 0 using the quadratic formula. Show all work! 75 points please help!!!!!

noname [10]

Answer:

$x=\dfrac{3+ \sqrt{29}}{2}, \quad \dfrac{3- \sqrt{29}}{2}$

Step-by-step explanation:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Given quadratic equation:

$x^2-3x-5=0$

Define the variables:

$\implies a=1, \quad b=-3, \quad c=-5$

Substitute the defined variables into the quadratic formula and solve for x:

$\implies x=\dfrac{-(-3) \pm \sqrt{(-3)^2-4(1)(-5)}}{2(1)}$

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Therefore, the exact solutions to the given quadratic equation are:

$x=\dfrac{3+ \sqrt{29}}{2}, \quad \dfrac{3- \sqrt{29}}{2}$

Learn more about the quadratic formula here:

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1 year ago

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