Answer:
<h2>The function f(x) = (x - 6)(x - 6) has only one x-intercept. But at (6, 0) not at (-6, 0).</h2>
Step-by-step explanation:
The intercept form of a quadratic equation (parabola):
![y=a(x-p)(x-q)](https://tex.z-dn.net/?f=y%3Da%28x-p%29%28x-q%29)
p, q - x-intercepts
Therefore
The function f(x) = x(x - 6) = (x - 0)(x - 6) has two x-intercepts at (0, 0) and (6, 0)
The function f(x) = (x - 6)(x - 6) has only one x-intercept at (6, 0)
The function f(x) = (x + 6)(x - 6) = (x - (-6))(x - 6)
has two x-intercept at (-6, 0) and (6, 0)
The function f(x) = (x + 1)(x + 6) = (x - (-1))(x - (-6))
has two x-intercepts at (-1, 0) and (-6, 0).
Answer:
D. 0.85
Step-by-step explanation:
In order to do this, you need to take from top and bottom. So, we can take a 12 from top and bottom and get:
3af^8/a^5f^2
Now, take a from top and bottom:
3f^8/a^4f^2
Finally, take f² from both:
3f^6/a^4
Hope this helped!
Answer:
(x-6)(x-6)
Step-by-step explanation:
![x^{2} - 12x + 36](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-%2012x%20%2B%2036)
= (x-6)(x-6)