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WINSTONCH [101]
2 years ago
10

Jessica biked for 130 minutes. Ella biked for 170 minutes.

Mathematics
2 answers:
Masja [62]2 years ago
5 0
The answer is C. 130+40
tatyana61 [14]2 years ago
4 0
The answer is c. 130+40 Chloe is correct.
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100 POINTS PLUS BRAINLIEST QUESTION ATTACHED
jonny [76]

A squared + B squared = C squared  

57 squared + 76 squared =  

(Distance between Southville and Westfield) squared  

square root of (3249 + 5776) = Distance between Southville and Westfield  

square root of 9025 = Distance between Southville and Westfield  

Distance between Southville and Westfield = 95 miles


Hope this helps! God bless :-)

3 0
3 years ago
Read 2 more answers
Find the image of the given point under the given translation!!!! help please!!!!​
harkovskaia [24]

Answer:

P' = (7, - 8)

Step-by-step explanation:

Under the given translation (x + 4, y - 3)

Add 4 to the x- coordinate of P and subtract 3 from the y- coordinate of P

P' = (3 + 4, - 5 - 3 ) = (7, - 8)

7 0
3 years ago
A hot air balloon travels 18miles in 3 hours. At this rate how many miles will the hot air balloon travel in 3/4hour?
Nikolay [14]

Answer:

4,5 miles

Step-by-step explanation:

In 1 hour:    18/3 = 6 miles

6 . 3/4 = 18/4 = 4,5 miles

3 0
2 years ago
The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grad
Leya [2.2K]
<h3><u>Answer with explanation:</u></h3>

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. Q_1 = 14

Median or second quartile i.e. Q_2 = 18

Third quartile or upper quartile i.e. Q_3 =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. Q_1 = 26

Median or second quartile i.e. Q_2 = 30

Third quartile or upper quartile i.e. Q_3 = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

  • The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
  • And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e. Q_3-Q_1

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

8\times n=12\\\\n=\dfrac{12}{8}\\\\n=\dfrac{3}{2}\\\\n=1.5

Hence, the number is : 1.5

6 0
3 years ago
Sarah has 273 feet of wire to make bead necklaces. If each necklace requires 1 2/3 feet of wire, how many necklaces can she make
o-na [289]

Oh boy, here we go again

First we must convert  1 2/3 to an improper fraction.  By doing this, we get 5/3  (3/3 + 2/3)

So now we have 273 /  5/3

To divide this easier we can do something that when I learned it was called (keep, change, flip)  which basically means keep the first fraction, change the sign from division to multiplication, and flip the second fraction

This now turns into:  273/1 * 3/5

Combine 273 and 3/5

273⋅3/5

Multiply 273

by 3

819/5

is your answer

5 0
3 years ago
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