Because there are 4 students who passed in all subjects, we can say that only 2 students passed in English and Mathematics only, only 3 students passed in Mathematics and Science only, and no one passed in English and Science only.
Given that we have deduced the number of students who passed in two subjects, we can now solve for the number of students who passed only one subject.
English = 15 - (4 + 2 + 0) = 9
Mathematics = 12 - (4 + 3 + 2) = 3
Science = 8 - (4 + 3 + 0) = 1
1. In English but not in Science,
9 + 2 = 11
2. In Mathematics and Science but not in English
3 + 3 + 1 = 7
3. In Mathematics only
= 3
3. More than one subject only
3 + 4 + 2 + 9 = 18
It will really be helpful if you draw yourself a Venn Diagram for this item.
Option D is correct. The correct statement that represents the graph is R: {y E R | y ≥ -3}
From the given graph, we are to get the range.
The range is the output value for which the function of the graph exists. The required output values are the y-values.
From the graph shown, we can see that the range of y is from -3 to 1. This can be denoted as;
Range = [-3, 1)
This shows that the range of the graph are all the values greater than -3 including -3.
The correct statement will therefore be;
R: {y E R | y ≥ -3}
Learn more about range here: brainly.com/question/17611901
Shift the decimal points of both 8.7 and 53.07 to the right by 2 decimal places.
(This is needed to convert 53.07 to 5307, since long division must divide by a whole number.)
870/5307
Set up the long division.
5307|870
Therefore your answer should be 0.1639.
Hope I help! Please check my questions please. I need major help on the question.
Answer:
-12
Step-by-step explanation:
Let b = -1 and a = -3
The average rate of change = 
f(b) = f(-1) = 3(-1)^2 - 5 = 3 - 5 = -2
f(a) = f(-3) = 3(-3)^2 - 5 =27 - 5 = 22
f(b) - f(a) = -2 - 22 = -24
b - a = -1 + 3 = 2
= -24/2 = -12
