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3 years ago

What set of reflections would carry kite ABCD onto itself?

Mathematics

2 answers:

yulyashka [42]3 years ago

8 0

goblinko [34]3 years ago

7 0

Answer:

Set of reflections would carry same figure y-axis, x-axis, y-axis, x-axis.

B is correct.

Step-by-step explanation:

We are given a kite ABCD. We need to find set of reflection would carry same figure.

Original figure in II quadrant.

Transform Original figure to Figure 1: Reflection across y-axis T(x,y)→(-x,y). Please see the attachment. (In first quadrant)

Transform Figure 1 to Figure 2: Reflection across y-axis T(x,y)→(x,-y). Please see the attachment. (In IV quadrant)

Transform Figure 2 to Figure 3: Reflection across y-axis T(x,y)→(-x,y). Please see the attachment. (In III quadrant)

Transform Figure 3 to Figure 4: Reflection across x-axis T(x,y)→(x,-y). Please see the attachment. (In II quadrant)

We can see figure 4 is equivalent to original figure.

Thus, Set of reflections would carry same figure y-axis, x-axis, y-axis, x-axis.

You might be interested in

Janaya buys a postcard from each travel destination she visits. Before starting her travels this year, Janaya had 20 postcards.

MrRa [10]

Answer:

The percentage increase in Jayana's postcard collection is 15%

Step-by-step explanation:

Jayana had 20 postcards last year

With 3 more postcards this year

From the given equation Quantity = Percent x Whole

Here;

Let P = Percent/100%

Quantity = Increment in postcard = 3 postcards

Whole = The total postcards from last year = 20 postcards

Hence,

3 postcards = P x 20 postcards

P = 3/20 = 0.15

Recall P = Percent/100%

∴ Percent = P x 100% = 0.15 x 100% = 15%

The percentage increase in Jayana's postcard collection is 15%

4 0

3 years ago

A tree trunk is pulled with a force of 3200 pounds by a truck’s cable that makes an angle of 25° with the horizontal. What is th

mr_godi [17]

Answer:

The vertical component of the force correct to the nearest pound Is

1352 pound

Step-by-step explanation:

Kindly find attached for your reference

This problem bothers on the topic of work energy and power

Given data

Applied force = 3200 pounds

Angle of application = 25°

We know that the horizontal force =

F= 3200cos 25°

Hence the vertical component of this force = F= 3200sin 25

=3200*0.42261

= 1352.352

to the nearest pound

F = 1352pound

3 0

3 years ago

How do I do this? Help!

Hitman42 [59]

Notice the picture below

you have two triangles, and you have the opposite and adjacent sides

thus, recall your SOH CAH TOA $\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}$

anyhow.. the one that has only
the angle
the opposite
and the adjacent

is Ms Tangent, so lets ask her some

$\bf tan(29^o)=\cfrac{x}{y}\implies y\cdot tan(29^o)=x
\\\\\\
tan(25^o)=\cfrac{x}{100-y}\implies (100-y)tan(25^o)=x\\\\
-----------------------------\\\\
x=x\qquad thus\qquad y\cdot tan(29^o)=(100-y)tan(25^o)$

solve for "y"