A) p + n + d = 18 B) .01p + .05n + .10d = 1.14 C) 2p = d
Substituting C) into A) A) p + n + 2p = 18 equals A) 3p + n = 18 Substituting C) into B) B) .01p + .05n + .10 *2p = 1.14 B) .01p + .05n + .2p = 1.14 B) .21p + .05n = 1.14 Taking equation A) A) 3p + n = 18 and multiplying it by -.05 A) -.15p -.05n = -.90 Then adding this to B) B) .21p + .05n = 1.14 .06p = .24 Therefore there are 4 pennies. (I'll leave it to you to determine the nickels and dimes.) ************************************************************************** Oh what the heck, I'll finish it for you.
Looking at equation C) C) 2p = d We know there are 4 pennies so there are: 2 *4 = eight dimes Looking at Equation A) A) p + n + d = 18 we can fill in the pennies and the dimes: A) 4 + n + 8 = 18 Therefore, there are 6 nickels.
