First you need to know some rules 2 numbers that are the same with coefficients divided : you differentiate those coeff
and multyplied :you sum up them
12x^8/3x^3= 4x^8-3=4x^5
20^2x=20^x*20^x
m^5*m^-7=m^5-7=m^-2
Answer:
-19
well i think it the answer
no, more than one triangle could be made with these measures
sss
(x, y) = (
,
)
given the 2 equations
5x - 3y - 10 = 0 → (1)
x + y - 7 = 0 → (2)
rearrange (2) to obtain y in terms of x
y = 7 - x → (3)
Substitute y = 7 - x into (1)
5x - 3(7 - x) - 10 = 0
5x - 21 + 3x - 10 = 0
8x - 31 = 0 ( add 31 to both sides )
8x = 31 ( divide both sides by 8 )
x = 
Substitute this value into (3) for y
y = 7 - x =
-
= 