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Nataliya [291]
3 years ago
8

Please help asap 20 pts

Mathematics
1 answer:
My name is Ann [436]3 years ago
8 0
C because 5 is (5,0)
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Six copies of the sum of nine fifths and three ​
fgiga [73]

Answer: What is the complete question? Can you comment it?

Step-by-step explanation: I can’t help unless I know what the full question is. Sorry.

5 0
3 years ago
Factor each expression.<br><br> (9) 5a - 25<br><br> (10) 28 - 7x<br><br> (11) 12z + 28 - 7z - 3
Nimfa-mama [501]

Answer:

Step-by-step explanation:

Look for the GCF and then divide every term by the GCF to see what remains

(9) 5a - 25  ( GCF is 5 so take out 5 and divide every term by 5)

     5(a-5)

(10) 28 - 7x     ( GCF is 7 so take out 7 and divide every term by 7)

     7(4-x)

(11) 12z + 28 - 7z - 3=  (combine terms) =

       5x+25( GCF is 5 so take out 5 and divide every term by 5)

        5(x+5)

6 0
3 years ago
What is the max number of slices of pizza can you get out out of 6 cuts?
Stells [14]
12 slices would be max
8 0
3 years ago
Read 2 more answers
What is the midpoint of the segment shown below (-11,0) (9,-1)
marissa [1.9K]

Answer:

(-1, -1/2)

Step-by-step explanation:

M= (Xa+Xb/2, Ya + Yb/2)


M= -11+9/2  ,  0 + -1/2

M = -2/2, -1/2

M=(-1, -1/2)

6 0
3 years ago
Read 2 more answers
Find the area lying outside r=6cos(theta) and inside r=3+3cos(theta)
Sloan [31]
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b... 

<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>

<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
<span>.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] </span>
<span>= 3θ/2 +sin(2θ) - sin(θ) </span>

<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>
7 0
3 years ago
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