The polynomial equation x^3-4x^2+2x+10=x^2-5x-3 has complex roots 3+-2i What is the other root? Use a graphing calculator and a
system of equations.
A. -3
B. -1
C. 3
D. 10
Please hurry!
A. -3
B. -1
C. 3
D. 10
Please hurry!
1 answer:
Answer:
B. -1
Step-by-step explanation:
x^3-4x^2+2x+10=x^2-5x-3
We know it has 3 roots since it is a 3rd degree polynomial.
Two of the roots are (3+2i) and (3-2i)
Subtract x^2-5x-3 from both sides
x^3-4x^2+2x+10-(x^2-5x-3)=x^2-5x-3 -(x^2-5x-3)
Distribute the minus sign
x^3-4x^2+2x+10-x^2+5x+3=x^2-5x-3 -x^2+5x+3
x^3 -5x^2+7x +13 =0
Graphing this equation , we see that it crosses the x axis at x=-1
That covers the three roots, 1 real and two complex
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Answer:
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Step-by-step explanation:
Given:
In ΔABC and ΔFDE
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