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lys-0071 [83]
3 years ago
5

Find BC round to the nearest tenth

Mathematics
1 answer:
slega [8]3 years ago
3 0

Answer:

6.7

Step-by-step explanation:

Here, we can apply cosine law, c^2=a^2+b^2-2abcos\theta

We the plug in values: (CB)^2+6^2+5^2-2*6*5*cos74

and solve that CB is around 6.7

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y²-y¹/x²-x¹

(-5)-(16)/(-12)-(-12)

-21/0

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HELP
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What is the volume of the composite figure? (Round to the nearest hundredth. Use 3.14 for x.)
marshall27 [118]

The volume of the composite figure is the third option 385.17 cubic centimeters.

Step-by-step explanation:

Step 1:

The composite figure consists of a cone and a half-sphere on top.

We will have to calculate the volumes of the cone and the half-sphere separately and then add them to obtain the total volume.

Step 2:

The volume of a cone is determined by multiplying \frac{1}{3} with π, the square of the radius (r²) and height (h). Here we substitute π as 3.1415.

The radius is 4 cm and the height is 15 cm.

The volume of the cone :

V = \frac{1}{3} \pi r^{2} h = \frac{1}{3} (3.1415)(4^{2} )(15) = 251.32 cubic cm.

Step 3:

The area of a half-sphere is half of a full sphere.

The volume of a sphere is given by multiplying \frac{4}{3} with π and the cube of the radius (r³).

Here the radius is 4 cm. We take π as 3.1415.

The volume of a full sphere \frac{4}{3} \pi r^{3} = \frac{4}{3} (3.1415) (4^{3}) = 268.07 cubic cm.

The volume of the half-sphere =\frac{1}{2} (268.07) = 134.037 cubic cm.

Step 4:

The total volume = The volume of the cone + The volume of the half sphere,

The total volume 251.32+134.037 = 385.357 cub cm. This is closest to the third option 385.17 cubic centimeters.

5 0
4 years ago
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