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lys-0071 [83]
3 years ago
5

Find BC round to the nearest tenth

Mathematics
1 answer:
slega [8]3 years ago
3 0

Answer:

6.7

Step-by-step explanation:

Here, we can apply cosine law, c^2=a^2+b^2-2abcos\theta

We the plug in values: (CB)^2+6^2+5^2-2*6*5*cos74

and solve that CB is around 6.7

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Phantasy [73]

Answer:

It is the third number Line

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2 years ago
The length f a rectangle is 3 ties its width, the perimeter of it is 24cm. what is the area of it?
andreyandreev [35.5K]

Answer: 27cm²

Step-by-step explanation:

lets take the width as x and length as 3x( since length is 3 times the width)…

Perimeter of the rectangle is 24 cm( 2*(l+b))= 2×(3x+x):24

2×4x=24

8x=24

X( width): 24/8=3cm

Length= 3x: 3*3=9cm

Area of the rectangle: ( l*w)= 9×3: 27cm²

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3 years ago
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What does "sum" mean in math?
Alexxx [7]
In math the sum means to add
6 0
3 years ago
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Please any one help me ​
Ulleksa [173]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Since it's a Trapezoid with its non - parallel sides equal to one another,

\qquad \sf  \dashrightarrow \:\angle A + \angle P = 180

[ By forming co - interior angle pair ]

\qquad \sf  \dashrightarrow \:\angle A +100 = 180

\qquad \sf  \dashrightarrow \:\angle A = 180 - 100

\qquad \sf  \dashrightarrow \:\angle A = 80

Now, similarly,

\qquad \sf  \dashrightarrow \:\angle A + \angle R = 180

\qquad \sf  \dashrightarrow \: \angle R + 80 = 180

\qquad \sf  \dashrightarrow \: \angle R  = 100

Similarly,

\qquad \sf  \dashrightarrow \angle K + \angle R = 180

\qquad \sf  \dashrightarrow \angle K + 100 = 180

\qquad \sf  \dashrightarrow \angle K  = 80

3 0
2 years ago
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HELP ASAP!!!! SO STUCK ON THIS! Will give brainliest IF CORRECT! :) please help! Be sure please!
vlada-n [284]
If I can read the #'s correctly:
add the yes answers together 23+147 = 170
add the no answers together 112+48= 160

so your ratio of haves to have nots is 170 to 160

but both sides can be divided by 10, so it can be simplified to 17 to 16.

Good Luck!
4 0
3 years ago
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