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Vilka [71]
3 years ago
15

Please help as soon as possible

Mathematics
2 answers:
Temka [501]3 years ago
6 0
24 MM(is the answer for your question!)
Zolol [24]3 years ago
5 0

Answer:

Diameter = 24 mm

Step-by-step explanation:

Volume of a sphere is 4/3 πr^{3}

First, we solve for radius:

2304π = 4/3πr^{3}

Multiply both sides by 3

3(2304π) = 4πr^{3}

Divide both sides by 4π

6912π/4π = r^{3}

1728 = r^{3}

Cuberoot both sides

\sqrt[3]{1728} = r

r= 12

Hence, the diameter would be: 2times the radius = 2*12= 24 mm

Hope this helps!

Please mark brainliest if you think I helped!

Would really appreciate!

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Coach Kirby is forming dodgeball teams from students in her physical education class.
Cloud [144]

Answer:

6x<48

Step-by-step explanation:

ik its this one because theres 48 players and 6 teams both are even numbers so if you did 48÷6x you would get 8 but theres fewer than 48 kids

6 0
2 years ago
Please review the following attachment. Thanks!
vaieri [72.5K]

Answer:

C: I and III only.

Step-by-step explanation:

We have two numbers x and y such that:

-y

And we want to determine which of the following conditions must be true.

First, let's examine the third condition. We have:

y>0

To see if this is true, let's try a negative value for y. So, let's use -7. This will give:

-(-7)

Simplify:

7

This is saying we need a number less than -7 and greater than 7.

This is impossible. So, y <em>must be</em> greater than 0.

Therefore, Condition III must be true.

Next, let's see this compound inequality visually.

Picture the following number-line:

<----------(-y)----------0----------y---------->

Whatever y is, -y is just y on the negative side.

Now, since our condition is that -y<x<y, this means that our x can be anywhere between -y and y. Namely:

<----------(-y)----------0----------y---------->

To determine our correct condition, let's picture x anywhere on the bolded lines. I'm just going to put x here...

<----------(-y)-------(x)--0----------y---------->

Now, remember the alternative definition for absolute value. Namely, the absolute value of x is also the <em>distance</em> from 0 to x. And this distance is always positive.

Since our x is between -y and y, our distance from 0 to x will always be less than the distance from 0 to either y.

Therefore, Condition I is also true.

Let's try an example. Let's let y = 9. So, -y=-9. And let's let x be between 9 and -9, say, -2. So:

<---(-9)-----(-2)--0--------(9)------>

We can see that:

|-2|=2\stackrel{\checkmark}{

Also, this example counters Condition II, as our x can indeed be negative if we desire it.

Algebraically, if we have a negative x such that:  

-y

We can divide everything by -1 to obtain:

y>x>-y

We can flip this to get:

-y

Which is our original inequality. So, Condition II does not need to be true.

So, the two conditions that <em>must</em> be true is I and III.

So, our answer is C.

3 0
3 years ago
Hi i'm stup*d at math and im not sure :(
pashok25 [27]

Answer:

I think standard form would be best because it is simplest.

Step-by-step explanation:

hope this helps

6 0
3 years ago
Read 2 more answers
What is 1/4 times 2/4
boyakko [2]
1/4= 0.25
2/4= 1/2 = 0.5
0.25 x 0.5 = 0.125
0.125 = 1/8
8 0
3 years ago
Suppose that a factory manufactures only tables and chairs and that the profit on one chair is $15 and on the table is $20. Each
Leya [2.2K]

Answer:

The data we have is:

Profit per chair = $15

Profit per table = $20

Chair needs: 1 large pice, 2 small pieces.

Table needs: 2 large pieces, 2 small pieces.

You have 6 large pieces and 8 small pieces, and you want to maximize the profit.

Let's define:

T = # of tables

C = # of chairs.

Total profit:

P = C*$15 + M*$20

The number of chairs that you can make is given by:

0 ≤ C ≤ 4

If you make 4 chairs, the profit is:

P = 4*$15 = $60

And there will be 2 large pieces left.

Now for the tables.

0 ≤ T ≤ 3

If you make 4 tables, the profit will be:

P = 3*$20 = $60 (same as before)

And there will be two small pieces left.

Then we want to use a medium number of tables and chairs, we can not use the maximum for any of those, the first thing we should try is:

we ideally would want to use all the pieces that we have.

8 small, 6 large:

Then we can make:

2 tables: we use 4 large pieces and 4 small pieces.

T = 2

And we have left 2 large pieces and 4 small pieces.

The leftover is enough to make two chairs.

C = 2.

In this case, where we used all our materials, the profit will be:

P = 2*$15 + 2*$20 = $30 + $40 = $70

The profit is maximized when we make 2 tables and two chairs.

5 0
4 years ago
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