The equation of a line is 6x-4y=11.

1 answer:

nataly862011 [7]3 years ago

3 0

Parallel - same slope so the line with parallel to it has a slope of 6
Perpendicular - opposite negative reciprocal so the perpendicular line should have a slope of 6 too or -6.

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Examine the linear table to find the slope, y-intercept, and write the equation for this linear relationship . NEED HELP PLEASE

gizmo_the_mogwai [7]

Answer:

$y = \frac{4}{3} x + 17$

Step-by-step explanation:

The table shows a set of x and y values, thus showing a set of points we can use to find the equation.

1) First, find the slope by using two points and substituting their x and y values into the slope formula, $\frac{y_2-y_1}{x_2-x_1}$ . I chose (-3, 13) and (0,17), but any two points from the table will work. Use them for the formula like so:

$\frac{(17)-(13)}{(0)-(-3)} \\= \frac{17-13}{0+3} \\= \frac{4}{3}$

Thus, the slope is $\frac{4}{3}$ .

2) Next, identify the y-intercept. The y-intercept is where the line hits the y-axis. All points on the y-axis have a x value of 0. Thus, (0,17) must be the y-intercept of the line.

3) Finally, write an equation in slope-intercept form, or $y = mx + b$ format. Substitute the $m$ and $b$ for real values.

The $m$ represents the slope of the equation, so substitute it for $\frac{4}{3}$ . The $b$ represents the y-value of the y-intercept, so substitute it for 17. This will give the following answer and equation:

$y = \frac{4}{3} x + 17$

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Answer:

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