<span><span><span>2<span>c5</span></span>+<span>44<span>c4</span></span></span>+<span>242<span>c3</span></span></span><span><span><span>2<span>c5</span></span>+<span>44<span>c4</span></span></span>+<span>242<span>c3</span></span></span><span>=<span><span><span>2<span>c3</span></span><span>(<span>c+11</span>)</span></span><span>(<span>c+11</span><span>)</span></span></span></span>
No hablo expanol
7(z+2)-3z=44
7z+14-3z=44
7z-3z+14=44
4z+14=44
-14 -14
4z+14-14=44-14
4z+0=30
4z=30
1/4 1/4
(4z)/4=30/4
(4/4)z=15/2
1z=15/2
z=15/2
z=15/2
x=-3, y=1
Step-by-step explanation:
Given equations are:
2x-3y=-9 Eqn 1
x+y = - 2 Eqn 2
From eqn 2:

Putting x=-y-2 in eqn 1

Hence,
x=-3, y=1
Keywords: Linear equations, Variables
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Answer:
Step-by-step explanation:
Final concentration % = [grams of salt / mililiters of solution] * 100
grams of salt = grams of salt from solution 1 + grams of salt from solution 2
grams of salt from solution 1 = mililiters * %/100 = 80 mililiters * 0.25 g/mililiters = 20 g
grams of salt from solution 2 = mililiters *%/100 = x*0.10 g/mililiters = 0.1x
mililiters of final solution = mililiters from solution 1 + mililiters from solution 2
mililiters of final solution = 80 mililiters + x mililiters
=> Final concentration, % = [0,10x + 20 g] / [x + 80 mililiters] * 100