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bekas [8.4K]
3 years ago
9

Two angles inside the triangle that do no share a vertex with the exterior.

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0
Exterior angle I think
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If Elizabeth gets $5 per hour to babysit plus $4 extra for putting the children to bed, write a flrmula that could be used to fi
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I hope this helps

Answer is 5H+4=A
7 0
3 years ago
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Someone please explain how to do this problem? :)<br><br> Factor completely 2c5 + 44c4 + 242c3.
frez [133]
<span><span><span>2<span>c5</span></span>+<span>44<span>c4</span></span></span>+<span>242<span>c3</span></span></span><span><span><span>2<span>c5</span></span>+<span>44<span>c4</span></span></span>+<span>242<span>c3</span></span></span><span>=<span><span><span>2<span>c3</span></span><span>(<span>c+11</span>)</span></span><span>(<span>c+11</span><span>)</span></span></span></span>
8 0
3 years ago
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7(z+2)-3z=44 quiero que me ayuden a resolver este problema por favor
slega [8]
No hablo expanol

7(z+2)-3z=44
7z+14-3z=44
7z-3z+14=44
4z+14=44
-14        -14
4z+14-14=44-14
4z+0=30
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1/4  1/4
(4z)/4=30/4
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z=15/2
5 0
3 years ago
I need to solve for x and y. Any help is greatly appreciated! Thank you!
Inessa05 [86]

x=-3, y=1

Step-by-step explanation:

Given equations are:

2x-3y=-9     Eqn 1

x+y = - 2      Eqn 2

From eqn 2:

x=-y-2

Putting x=-y-2 in eqn 1

2(-y-2)-3y=-9\\-2y+4-3y=-9\\-5y-4=-9\\Adding\ 4\ on\ both\ sides\\-5y-4+4=-9+4\\-5y=-5\\Dividing\ both\ sides\ by\ -5\frac{-5y}{-5}=\frac{-5}{-5}\\y=1\\Putting\ y=1\ in\ eqn\ 2\\x+1=-2\\Subtracting\ 1\ from\ both\ sides\\x+1-1=-2-1\\x=-3

Hence,

x=-3, y=1

Keywords: Linear equations, Variables

Learn more about linear equations at:

  • brainly.com/question/4034547
  • brainly.com/question/4054269

#LearnwithBrainly

3 0
3 years ago
A pharmacist has 80 milileters of a 25 percent saline solution. Which expression can be used to find the percentage of the conce
Thepotemich [5.8K]

Answer:


Step-by-step explanation:

Final concentration % = [grams of salt / mililiters of solution] * 100


grams of salt = grams of salt from solution 1 + grams of salt from solution 2


grams of salt from solution 1 = mililiters * %/100 = 80 mililiters * 0.25 g/mililiters = 20 g


grams of salt from solution 2 = mililiters *%/100 = x*0.10 g/mililiters = 0.1x


mililiters of final solution = mililiters from solution 1 + mililiters from solution 2


mililiters of final solution = 80 mililiters + x mililiters


=> Final concentration, %  =  [0,10x + 20 g] / [x + 80 mililiters] * 100


6 0
3 years ago
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