Answer:
40 miles away from home
To put it in yard would be 82,720
Step-by-step explanation:
According to the probabilities given, it is found that the correct option regarding the independence of the events is given by:
No, P(carry cash) != P(carry cash|have children).
<h3>What is the probability of independent events?</h3>
If two events, A and B, are independent, we have that:
Which also means that:
In this problem, we have that:
- 62% carry cash on a regular basis, hence P(cash) = 0.62.
- 46% has children, hence P(children) = 0.46.
- Of the 46% who have children, 85% carry cash on a regular basis, hence P(cash|children) = 0.85.
Since P(carry cash) != P(carry cash|have children), they are not independent.
More can be learned about the probability of independent events at brainly.com/question/25715148
Answer:
C. 4
Step-by-step explanation:
-1/2 * (-8)
Replace -8 with a fraction
-1/2 * -8/1
Multiply the numerators
-1 * -8 = 8
Multiply the denominators
2*1 =2
Put the numerator over the denominator
8/2 = 4
For this case we have to take into account the following conversion:
1 lb = 453.59 g
The weight of the cat in grams is:
(12) * (453.59) = 5443.08 grams
The weight of the cat in kilograms is:
(5443.08) * (1/1000) = 5.44308 Kg
Then, we calculate the number of milligrams needed:
amoxicillin at 5 mg / kg twice a day for seven days:
(2) * (7) * (5) = 70 (mg / (kg * day))
The number of milligrams per day is:
5.44308 * (70) = 381.0156 mg / day
Finally the number of mLs is:
(381.0156) / (50) = 7.62 mLs / day
Answer:
the cat will need 7.62 mLs per day