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Rudik [331]
4 years ago
14

Using the identity ( x+a) 9x+b) = x2 + (a+b)x +ab, find the following product: (4p+3q)(4p+7q)

Mathematics
1 answer:
Aleks [24]4 years ago
3 0

Answer:

(4p+3q)(4p+7q)=x^2+40pq+21q^2

Step-by-step explanation:

Given\ (x+a)(x+b)=x^2+(a+b)x+ab\ ...............................(1)\\\\We\ have\ to \find\ (4p+3q)(4p+7q)\\\\Compare\ (4p+3q)(4p+7q)\ with\ (x+a)(x+b)\\\\x=4p\\\\a=3q\\\\b=7q\\\\Substitute\ these\ values\ in\ eq(1)\\\\(4p+3q)(4p+7q)=x^2+(3q+7q)\times 4p+3q\times 7q\\\\(4p+3q)(4p+7q)=x^2+10q\times 4p+21q^2\\\\(4p+3q)(4p+7q)=x^2+40pq+21q^2

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