For #6
x + y = -10
x - y = 2
First solve for y in one of the equations
x - y = 2
-y = 2 - x
y = -2 + x
y = x - 2
Now substitute into one of the equations and solve for x
x + y = -10
x + x - 2 = -10
2x - 2 = -10
2x = -8
x = -4
Washington had 143 hits and Sanchez has 107 hits
Amber should’ve added -3 and 5 first instead of adding 5 and 4.
We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²
area of a circle=pi*r²
in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²
the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of the circle minus the area of 1 equilateral triangle
</span>so
[ (3/2)*pi in²-(9/4)*√3 in²]
the answer is
[ (3/2)*pi in²-(9/4)*√3 in²]
