Answer:
The perimeter (to the nearest integer) is 9.
Step-by-step explanation:
The upper half of this figure is a triangle with height 3 and base 6. If we divide this vertically we get two congruent triangles of height 3 and base 3. Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles: (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.
Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.
The lower half of the figure has the shape of a trapezoid. Its base is 4. Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle. Using the Pythagorean Theorem, we get
(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10. Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.
Then the perimeter consists of the sum 2√10 + 4 + 6√2.
which, when done on a calculator, comes to 9.48. We must round this off to the nearest whole number, obtaining the final result 9.
Base of parallelogram b = 24.5 cm
Step-by-step explanation:
We are given:
Perimeter =P= 63 cm^2
Slant Height =a= 7 cm
Base of Parallelogram =b= ?
The formula used is:
where a is height and b is base
Putting values:
So, Base of parallelogram b = 24.5 cm
Keywords: Perimeter of Parallelogram
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Answer:
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Answer:
x = 3
Step-by-step explanation:
5(x+1) = 20
x+1 = 20/5
or, x+1 = 4
or, x = 4-1
so, x = 3
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