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Mice21 [21]
3 years ago
15

Hi I need help :( Pls show your working..Will give brainliest for helpful answer​

Mathematics
1 answer:
Basile [38]3 years ago
5 0

Answer:

number 10

dy/dx =(dy/dt).(dt/dx)

now find

dy/dt=4t-1. , dt/dx=1

so : dy/dx=(4t-1).(1)

dy/dx= 4t-1 ,we have x=t-3-----> t=x+3

subtitute at t

dy/dx= 4(x+3)-1=4x+12-1= 4x+11

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Bob says that 5h and 5h^2 are like terms because they both have the variable h. Is Bob correct? Justify reasoning.
Dominik [7]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ Bob ISN'T correct. 5h^2 has an exponent of 2 while 5h only has an exponent of 1. 5h^2 and 5h are completely different due to the exponent.

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3 0
3 years ago
I need to know what this is
ycow [4]

Answer:

★\:\: \frac{3 {x}^{3} - 18 {x}^{2} + 27x}{2 {x}^{2} + 2x - 12}\:when\:x≠2,\:3   \\ =   \frac{3x( {x}^{2} - 6x + 9) }{2( {x}^{2} + x - 6) }  \\  =  \frac{3x( {(x)}^{2} - 2 \times (3) \times (x) + {(3)}^{2} ) }{2( {x}^{2} + 3x - 2x - 6) }  \\ =  \frac{3x {(x - 3)}(x - 3) }{2(x(x + 3) - 2(x + 3))}   \\ =  \boxed{‡ \frac{3x {(x - 3)}^{2} }{2(x + 3)(x - 2)}‡}✓

<h3><u>3x(x-3)²/2(x+3)(x-2)</u> is the right answer.</h3>
6 0
3 years ago
I need help with this
hjlf
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5 0
3 years ago
Here you go dude your points
faltersainse [42]

Answer:

Thank you SO much!♡♡♡♡♡♡

8 0
2 years ago
Read 2 more answers
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