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Shtirlitz [24]
4 years ago
8

Classify the figure in as many ways as possible.

Mathematics
1 answer:
Dima020 [189]4 years ago
3 0
The answer is D.

This figure has 4 sides which makes it a quadrilateral.

This figure has 2 sets of parallel sides which makes it a parallelogram.

This figure has 4 equal sides which makes it a rhombus.

This figure has 4 right angles which makes it a rectangle.

And this figure has both 4 equal sides and 4 equal angles which makes it a square.

To make it easier, all squares are: quadrilaterals, parallelograms, rhombuses, rectangles and of course squares.
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What is the value of 3 x squared minus 5 x y + 5 y squared for x = negative 6 and y = 2?
Klio2033 [76]

Answer:

A = 188

Step-by-step explanation:

+ replace x = -6 and y= 2 into 3 x squared minus 5 x y + 5 y squared = A

So A= 3x^2 - 5xy + 5y^2

A = 3 *(-6)^2 -5* (-6) *2 +5* 2^2

A = 3* 36 +60 + 5*4

A= 108 +60 +20

or A = 188

Have a good day

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Integer equivalent of 25 3/2
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Its 26.5 !! as (25×2+3)/2
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Find the equation of a circle centered on the origin going through the point (-5,3)
11111nata11111 [884]

The given center and point on the circle of (0,0) and (-5, 3), respectively

gives the equation of the circle as x^{2} +y^{2} =\sqrt{34}.

The general form of the equation of the circle is presented as follows

(x - h)² + (y - k)² = r²

Where,(h, k) is the center of the circle and r is the radius of the circle

Here (h, k) is centered about the origin and the radius of the circle

Radius of the circle = √[(-5-0)² + (3-0)²]

= √(25+9)

=√34.

The equation of a circle centered on the origin going through the point (-5,3)

x^{2} +y^{2} =\sqrt{34}

Learn more about the equation of a circle brainly.com/question/502872

#SPJ4

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