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3 years ago

There are 28 students in math class. 22 of them passed the test. What percentage passed the test?

1 answer:

8 0

In order to solve this question, we need to set up a proportion. We are trying to solve for a percentage, so the proportion will be 22/28 = x/100, where x is the percentage that 22 is out of 28.

22 / 28 = x / 100
2200 = 28x Cross multiply
x = 78.6% Divide

22 is about 78.6% of 28. Remember that, whenever you need a percentage, just set up a proportion like this one.

Hope this helps!

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Which is the solution set of a for -3(-x a) 7<5 when x=-1 ?

masha68 [24]

Answer: CAN I DO YOU PLS

Step-by-step explanation:

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2 years ago

The product of 43x6 can be broken down into expand form

o-na [289]

Answer:yes

Step-by-step explanation:

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2 years ago

Read 2 more answers

Use geometric series to find the fraction of 0.8967898989

Sliva [168]

I'm guessing the repeating part is 89 at the end, so that

$x=0.8967\overline89\implies10^4x=8967.\overline{89}$

Then

$10^4x=8967+\displaystyle89\sum_{i=1}^\infty\frac1{100^i}$

$10^4x=8967+89\left(\dfrac1{1-\frac1{100}}-1\right)$

$10^4x=8967+\dfrac{89}{99}$

$x=\dfrac{8967}{10^4}+\dfrac{89}{99\cdot10^4}$

$x=\dfrac{443911}{495000}$

###

An arguably quicker way without using geometric series:

$10^4x=8967.\overline{89}$

$10^6x=896789.\overline{89}$

$10^6x-10^4x=887822$

$x=\dfrac{887822}{10^6-10^4}=\dfrac{443911}{495000}$

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3 years ago

What is the slope of the line that passes through the points (9,60 and (14,7)?

bija089 [108]

This is (y2-y1)/(x2-x1), y2 being 12, y1 being 7, x2 being -39 and x1 being 26. So if you plug in the points it would be: (12-7)/(-39-26). This solved equals: -5/65 which simplified equals: -1/13

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3 years ago

A is (-2,1)

valkas [14]

1) in order to solve this problem you must to obtain The value of K, for it you know by definition that the horizontal slope of the side BC is zero ,

then m = Y2-Y/X2-X1, 0 = 5-K/4-6⇒0 = 5-K⇒K = 5

known this value for K you ca find the equation of thE line that pass through A and C

2) Following the same procedure in first place you calculate the slope with the points A(-2,1) Y C ( 4,5)

m= 5-1/4-(-2) = 2

now with any point A or C and the slope you obtain the line

A(-2,1)

y-y1 = m (x-x1) , Y-1= 2(X-(-2)⇒Y-1= 2X+4⇒Y=2X+4-1⇒Y =2X+3

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3 years ago