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Hunter-Best [27]
3 years ago
12

Mary decides to take out a $4,000 student loan this year. If she will pay 10% interest compounded annually, how much will the to

tal loan amount be in four years when she graduates?
Mathematics
1 answer:
kogti [31]3 years ago
6 0

Answer 4000+1600= 5600

Step-by-step explanation:

The 10% is $400. 400 times 4 is 1600. So to find the total, its 5600. Mark brainliest if this helped you

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lara31 [8.8K]
Your answer is 0. Its easy.
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3 years ago
Use the grouping method to factor the polynomial below completely 3x^3+9x^2+5x+15​
Tomtit [17]

Answer:

(x+3)( 3x^2 +5)

Step-by-step explanation:

3x^3+9x^2+5x+15​

Split into two groups

3x^3+9x^2     +5x+15​

Factor 3x^2 out of the  first group and 5 out of the second group

3x^2 ( x+3)  + 5(x+3)

Factor out x+3

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6 0
3 years ago
Suppose a marketing company computed a 94% confidence interval for the true proportion of customers who click on ads on their sm
Ksivusya [100]

Answer:

d. There is a 98% chance that the true proportion of customers who click on ads on their smartphones is between 0.56 and 0.62.

Step-by-step explanation:

Confidence interval:

x% confidence

Of a sample

Between a and b.

Interpretation: We are x% sure(or there is a x% probability/chance) that the population mean is between a and b.

In this question:

I suppose(due to the options) there was a small typing mistake, and we have a 98% confidence interval between 0.56 and 0.62.

Interpreation: We are 98% sure, or there is a 98% chance, that the true population proportion of customers who click on ads on their smartphones is between 0.56 and 0.62. Option d.

3 0
4 years ago
How do I add and subtract radicals with no like terms
liq [111]

Most real number arithmetic is pretty vacuous

\sqrt 2 + \sqrt 3 = \sqrt{2} + \sqrt{3}

That's about as good a way as possible to write this particular real number. But it's far from the only way.

(\sqrt 2 + \sqrt 3)^2 = \sqrt{2}^2 + 2\sqrt 2 \sqrt 3 + \sqrt{3}^2 = 5 + 2 \sqrt 6

so

\sqrt 2 + \sqrt 3 = \sqrt{5 + 2 \sqrt 6}

Sometimes you can factor something out and you have a common radical:

\sqrt{32} + \sqrt{128} = \sqrt{2^5} + \sqrt{2^7} = 4 \sqrt{2} + 8 \sqrt{2} = 12 \sqrt{2}

But most of them are vacuous,

3\sqrt{7} + 34 \sqrt{13} = 3\sqrt{7} + 34 \sqrt{13}


8 0
4 years ago
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