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Advocard [28]
3 years ago
12

Find the interquartile range for a data set having the five-number summary: 7.8, 17.1, 23.6, 31.1, 36.9

Mathematics
2 answers:
MakcuM [25]3 years ago
5 0

Answer:

Interquartile Range: 21.549999999999997 = 21.55

Step-by-step explanation:

lorasvet [3.4K]3 years ago
4 0
Please answer please please thank you
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In a widget factory, machines A, B, and C manufacture, respectively, 20, 30, and 50 percent of the total. Of their output 6, 3,
steposvetlana [31]

Answer:

38.71% probability it was manufactured by machine A.

29.03% probability it was manufactured by machine B.

32.26% probability it was manufactured by machine C.

Step-by-step explanation:

We have these following probabilities:

A 20% probability that the chip was fabricated by machine A.

A 30% probability that the chip was fabricated by machine B.

A 50% probability that the chip was fabricated by machine C.

A 6% probability that a chip fabricated by machine A was defective.

A 3% probability that a chip fabricated by machine B was defective.

A 2% probability that a chip fabricated by machine C was defective.

The question can be formulated as:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

What are the probabilities that it was manufactured by machines A, B, and C?

Machine A

What is the probability that the widget was manufactures by machine A, given that it is defective?

P(B) is the probability that it was manufactures by machine A. So P(B) = 0.20

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine A. So P(A/B) = 0.06

P(A) is the probability that a widget is defective. This is the sum of 6% of 20%, 3% of 30% and 2% of 50%. So

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.2*0.06}{0.031} = 0.3871

38.71% probability it was manufactured by machine A.

Machine B

What is the probability that the widget was manufactures by machine B, given that it is defective?

P(B) is the probability that it was manufactures by machine B. So P(B) = 0.30

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine B. So P(A/B) = 0.03

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.03}{0.031} = 0.2903

29.03% probability it was manufactured by machine B.

Machine C

What is the probability that the widget was manufactures by machine C, given that it is defective?

P(B) is the probability that it was manufactures by machine C. So P(B) = 0.50

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine C. So P(A/B) = 0.02

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.02}{0.031} = 0.3226

32.26% probability it was manufactured by machine C.

6 0
3 years ago
The tallest tree in the world is 379 feet tall. How tall will each of the trees be in the year 2030 if their models continue? Is
tresset_1 [31]

Models are patterns that are used to predict measurements and populations

<h3>How to model the tree</h3>

The question is incomplete, as the model and the dataset to model that growth of the tree are not given.

So, I will give a general explanation

If the model of the tree follows a linear model (e.g y = 2x + 3), then the model is not reasonable.

This is so because, population and growth cannot be measured by a linear model

However, if the growth of the trees follow an exponential model (e.g y = 2(3)^x), then the model is reasonable

Read more about mathematical models at:

brainly.com/question/24282972

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2 years ago
A seller buys an item from a manufacturer for $100 and sells it to a customer for $120. which of these terms describes this extr
SashulF [63]
Markup: The amount added to the cost price of goods to cover overhead and profit.
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Which statement is true about angles 3 and 5?
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They are Complementary
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3 years ago
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Gertrude has 83.21 centimeters of wire. She uses 2 pieces of the wire.
natta225 [31]

Answer:W0t thu Ars £init

Step-by-step explanation:

8 0
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