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Advocard [28]
3 years ago
12

Find the interquartile range for a data set having the five-number summary: 7.8, 17.1, 23.6, 31.1, 36.9

Mathematics
2 answers:
MakcuM [25]3 years ago
5 0

Answer:

Interquartile Range: 21.549999999999997 = 21.55

Step-by-step explanation:

lorasvet [3.4K]3 years ago
4 0
Please answer please please thank you
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Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
What is 1 1/2 multiplied by 2 as a mixed number or fraction
Andrew [12]

Answer:

3

Step-by-step explanation:

1 1/2 can be rewritten as 3/2, so 3/2*2=3.

6 0
3 years ago
Read 2 more answers
What is -5/8 + 3/4 I cannot seem to figure it out correctly thanks!
Pepsi [2]

Step-by-step explanation:

-5/8 + 3/4

= -5/8 + 6/8

=1/8

7 0
2 years ago
Rhombus A has a base of 7 inches and an area of 35 square inches. Rhombus B has a base and height that are three times the base
STALIN [3.7K]
For rhombus A:
base = 7 in
area = 35 in²

Area of rhombus = b * h
⇒ 35 = 7 * h
⇒ h = 35/7
⇒ h = 5 in

Rhombus B:
height = 3*5 = 15 in
base = 7*3 = 21 in
Area = 15 * 21 = 315 in²

Area of rhombus B is 9 times area of rhombus A. When the dimensions are increased to 3 times the initial dimension, area became 9 times.

8 0
3 years ago
Read 2 more answers
Need help with Slope
grigory [225]

Answer:

(0,-1)

Step-by-step explanation:

...

3 0
3 years ago
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