Equilateral triangle have the same side lengths. Perimeter = sum of all sides
(4x - 3) + (4x - 3) + (4x - 3) = 63
Remove parentheses
4x - 3 + 4x - 3 + 4x - 3 = 63
Combine like terms
12x - 9 = 63
12x = 72, x = 6
Solution: x = 6
Answer:

Step-by-step explanation:
In the diagram below we have
ABCD is a parallelogram. K is the point on diagonal BD, such that

And AK meets BC at E
now in Δ AKD and Δ BKE
∠AKD =∠BKE ( vertically opposite angles are equal)
since BC ║ AD and BD is transversal
∠ADK = ∠KBE ( alternate interior angles are equal )
By angle angle (AA) similarity theorem
Δ ADK and Δ EBK are similar
so we have


( ABCD is parallelogram so AD=BC)
( BC= BE+EC)


( subtracting 1 from both side )

taking reciprocal both side

Answer:
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Step-by-step explanation:
Answer:
Probablity of getting six in at most three roll= 0.199.
Step-by-step explanation:
Given: Dice rolled at most 3 times untill a 6 occurs.
First, finding the probablity of getting 6 in a dice if rolled once.
Probablity= 
We know, dice have six side, therefore, total number of event will be 6.
∴ Probablity of getting six in one roll= 
As given, Dice is rolled at most 3 times.
Now, finding the probablity of getting 6 in a dice if rolled 3 times.
∴ Probablity of getting six in three roll= 
⇒ Probablity of getting six in three roll= 
Taking LCD 216
⇒Probablity of getting six in three roll= 
⇒Probablity of getting six in three roll= 
∴Probablity of getting six in three roll=0.199