The mean weight of five complete computer stations is 167.2 pounds. The weights of four of the computer stations are 158.4 pound
2 answers:
The mean weight of five complete computer stations is 167.2 pounds.
The weights of four of the computer stations are 158.4 pounds, 162.8 pounds, 165 pounds, and 178.2 pounds.
We have to determine the weight of fifth computer station.
Let the weight of fifth computer station be 'x' pounds.
Mean is calculated by sum of all the observations divided by the total number of observations.
So,
x= 171.6 pounds
The weight of fifth computer station is 171.6 pounds.
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Answer:
Explanation is given below.
Step-by-step explanation:
Given:
Number of Trumpets = 40
Number of tubas = 35
Carlee says, the ratio of trumpets to tubas = 40 : 35
Danny says, the ratio of trumpets to tubas = 8 : 7
To explain why the two ratios are equivalent.
Solution:
Equivalent ratios are all ratios which are equal to each other in their reduced to simplest form.
The ratio of trumpets to tubas can be given as =
To reduce the ratio to its simplest form, we divide both numbers by their G.C.F.
The G.C.F. for 40 and 35 is 5.
So, we divide numerator and denominator by 5.
⇒
⇒
Thus, the simplest ratio of trumpets to tubas can be given as = 8:7
This is why both Danny and Carlee are correct with the ratios of trumpets to tubas.
Carlee gave the direct ratio, while Danny gave the simplest ratio.
Answer:
<em>Any width less than 3 feet</em>
Step-by-step explanation:
<u>Inequalities</u>
The garden plot will have an area of less than 18 square feet. If L is the length of the garden plot and W is the width, the area is calculated by:
A = L.W
The first condition can be written as follows:
LW < 18
The length should be 3 feet longer than the width, thus:
L = W + 3
Substituting in the inequality:
(W + 3)W < 18
Operating and rearranging:
Factoring:
(W-3)(W+6)<0
Since W must be positive, the only restriction comes from:
W - 3 < 0
Or, equivalently:
W < 3
Since:
L = W + 3
W = L - 3
This means:
L - 3 < 3
L < 6
The width should be less than 3 feet and therefore the length will be less than 6 feet.
If the measures are whole numbers, the possible dimensions of the garden plot are:
W = 1 ft, L = 4 ft
W = 2 ft, L = 5 ft
Another solution would be (for non-integer numbers):
W = 2.5 ft, L = 5.5 ft
There are infinitely many possible combinations for W and L as real numbers.