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SOVA2 [1]
3 years ago
8

What is the least common multiple of 6, 18, and 8?

Mathematics
2 answers:
nexus9112 [7]3 years ago
6 0

Answer:

6 = 2 • 3  

8 = 23  

18 = 2 • 32

joja [24]3 years ago
3 0

Answer:

72

Step-by-step explanation:

Consider the least common multiple of 6 and 8

The multiples of 6 are : 6, 12, 18, 24, 30, 36, ......

The multiples of 8 are : 8, 16, 24, 32, 40, ......

The common multiple is 24 or 48 or 72

The multiples of 18 are : 18, 36, 54, 72, 90, ....

Since 72 is a common multiple of 8 and 6 and also a multiple of 72

Then the least common multiple of 6, 18 and 8 is 72

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Match each slope and y-intercept with the appropriate linear equation.
Bumek [7]

Answer:

m= 4, b = 3 matches with y = 4x +3

m=5, b = -2 matches with y = 5x - 2

m = 3, b = 4 matches with y = 3x + 4

m = -2, b=5 matches with y = -2x + 5

Step-by-step explanation:

Slope-intercept form is <em>y = mx + b</em><em> </em>in which m = slope and b = y-intercept

7 0
3 years ago
Read 2 more answers
A see-saw is 25 feet long with a fulcrum in the middle of the board. If a 60 lb. child sits three feet from the fulcrum, what is
My name is Ann [436]

Answer:

14.4 lb

Step-by-step explanation:

In a see-saw in equilibrium, the torque generated by one side needs to be the same generated in the other side. The torque is calculated by the product between the mass and the distance to the center of the see-saw.

The torque generated by the child is:

T1 = 60 * 3 = 180 lb*feet

So, the torque generated by the weight needs to be higher than T1 in order to lift the child.

The lowest mass is calculated when the mass is in the maximum distance, that is, 12.5 feet from the center.

So, we have that:

T2 = 180 = mass * 12.5

mass = 180/12.5 = 14.4 lb

So the lowest weight is 14.4 lb

4 0
3 years ago
When reading a grid reference number corresponding to a grid on a map, you read ______ the number first.
DENIUS [597]
Your answer is A. eastings
Let me know if you have another question ☺
3 0
3 years ago
Read 2 more answers
Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur
stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Three heads.
  • Event B: Fair coin.

The probability associated with 3 heads are:

  • 0.5^3 = 0.125 out of 0.5(fair coin).
  • 1 out of 0.5(biased).

Hence:

P(A) = 0.125 + 0.5 = 0.625

The probability of 3 heads and the fair coin is:

P(A \cap B) = 0.5(0.125) = 0.0625

Then, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0
3 years ago
Write an equation of the perpendicular bisector of the segment with endpoints U(-3,4) and V(9,8)
stealth61 [152]

Answer:

y=-3x+15

Step-by-step explanation:

the midpoint of UV (using the midpoint formula) is (3,6)

the slope of UV= 4/12= (1/3)

perpendicular slope is -3

now find line with slope -3 passing (3,6)

y-6=-3(x-3)

y=-3x+15

5 0
3 years ago
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