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3 years ago

Why is 5 to the 2 power also read as 5 squared

1 answer:

3 0

The reason for this has to do with finding the area of a square. When you are looking for the area of a square, you use the rectangle formula (since a square is also a rectangle).

The formula is Area = Length * Width

However, since in a square, the length and width are the same, both get changed to the word "Side". As a result, we get the following formula.

Area = Side * Side

This can be simplified to:

Area = Side^2.

Since each number to the second power also shows the area of a square with that given length sides, it can also be called "squared".

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I need help its math

shtirl [24]

Answer:

$x=47$ °

Step-by-step explanation:

4 0

3 years ago

1. The coefficient in the term 7xy is (a) 7 (b) 3 (c) 1 (d) 2

max2010maxim [7]

Answer:

1. 7

2.-5

4.20

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6.1

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19 .28p

hope this helps u

Step-by-step explanation:

I am unable to answer some questions

6 0

3 years ago

What percent of 43.75 is 70

murzikaleks [220]

62.5%
What I did was divided 43.75 by 70 to get 0.625.
Then I moved the decimal over two places to the right to get 62.5.

7 0

3 years ago

Can someone help me with these please.

ELEN [110]

Answer: Barbara did not include a variable in the term $1.49$ , which must represents the number of bottles of iced tea she needs to sell.

Step-by-step explanation:

Let be "x" the number of bottle of water Barbara needs to sell and "y" the number of bottle of iced tea she needs to sell.

She sells iced tea for $1.49 per bottle and water for $1.25 per bottle, so she can write the following equation in order to calculate the number of bottles she needs to sell to earn $100:

$1.25x + 1.49y = 100$

Since Barbara wrote this equation:

$1.25x + 1.49 = 100$

We can conclude that the error Barbara made in writing the equation was: She did not include a variable in the term $1.49$ , which must represents the number of bottles of iced tea she needs to sell.

8 0

3 years ago

A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of

GenaCL600 [577]

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 1.989.

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

$M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23$

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

8 0

3 years ago