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LenKa [72]
3 years ago
11

Write the equation that is the translation of y=|x| right 7 units and down 9 units.

Mathematics
1 answer:
DedPeter [7]3 years ago
8 0

Answer:

y=|x-7|-9.

Step-by-step explanation:

The given function is  y=|x|.

When this function is translated to the right 7 units and down 9 units, then the equation becomes

y=|x-7|-9.

Always remember that; y=|x-c|-k is a transformation that translates the graph of y=|x| c units to the right and k units down.

The correct choice is the first option.

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matteo is centering a poster on the back of the door that is 32 inches wide the poster is 18 1/2 inches wide how far from the ed
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All you have to do is subtract 18.5 from 32 = 13.5 and then divide that number by 2 for each side of the poster, 13.5 / 2 = 6.75 inches
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An oblique square prism is shown. An oblique square prism is shown. The square has side lengths with a measure of x. The distanc
dimaraw [331]

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Step-by-step explanation:

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3 years ago
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What are the roots of x in -10x2 + 12x − 9 = 0?
hoa [83]

Answer:

x_1=\frac{3(2+i\sqrt{6})}{10}

x_2=\frac{3(2-i\sqrt{6})}{10}

Step-by-step explanation:

Use the Quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac}}{2a}

You can identify that, in this case:

a=-10\\b=12\\c=-9

Now you need to substitute these values into the formula:

x=\frac{-12\±\sqrt{12^2-4(-10)(-9)}}{2(-10)}

x=\frac{-12\±\sqrt{-216}}{-20}

Remember that:

i=\sqrt{-1}

Therefore,rewriting and simplifying, you get:

x=\frac{-12\±6i\sqrt{6}}{-20}

x=\frac{-6(2\±i\sqrt{6})}{-2(10)}

x=\frac{3(2\±i\sqrt{6})}{10}

Then, you get the following roots:

x_1=\frac{3(2+i\sqrt{6})}{10}

x_2=\frac{3(2-i\sqrt{6})}{10}

6 0
2 years ago
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4,193x381=1,597,000 why is this product incorrect
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4,193x381=1,597,533
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2 years ago
What are the ratios for sin A and cos A? The triangle is not drawn to scale.
dalvyx [7]

Answer:

SinA = \frac{84}{85}  and  CosA=\frac{13}{85}

Step-by-step explanation:

The ratios of sine and cos are defined as follows:

Sin A = \frac{Opposite}{Hypotenuse} , and

CosA = \frac{Adjacent}{Hypotenuse}

The hypotenuse is always the side opposite of the 90 degree angle (for the given triangle, the hypotenuse is 85)

Since we are looking at the angle A, the opposite side with respect to A would be the side length of 84. That leaves the side 13 as the adjacent side.

Thus, we can now write:

Sin A = \frac{Opposite}{Hypotenuse}\\SinA = \frac{84}{85}

CosA = \frac{Adjacent}{Hypotenuse}\\CosA=\frac{13}{85}

The correct answer is  the first answer choice.

7 0
2 years ago
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