It's a line, it intersects two or more coplanar lines.
C(x) = 300.
Our question becomes simple: 300 = x^2-40x+610
x^2-40x+610-300 = 0
x^2-40x+310 = 0
Now find the value for x with either the quadratic formula or by factorization.
Let me know how it goes. Giving the full answer won’t help you improve
F(x) = 6x² + 5 - 42x
first step in writing the f(x) in vertex form? WRITE THE FUNCTION IN STANDARD FORM.
f(x) = 6x² - 42x + 5
Exponents must be in decreasing order.
Using this equation, f(3) = 23.
In order to find the value of f(3), we need to take the f(x) equation and put 3 everywhere we see x. Then we follow the order of operations to solve. So, let's start with the original.
f(x) = 2x^2 + 5sqrt(x - 2)
Now place 3 in for each x.
f(3) = 2(3)^2 + 5sqrt(3 - 2)
Now square the 3.
f(3) = 2(9) + 5 sqrt(3 - 2)
Do the subtraction inside of the parenthesis.
f(3) = 2(9) + 5sqrt(1)
Take the square root
f(3) = 2(9) + 5(1)
Multiply.
f(3) = 18 + 5
And add.
f(3) = 23
If the number is y then the inequality is
twice the difference of y and 7=2(y-7)
at most- 20=less than or equal to
2(y-7)≤-20
