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Thepotemich [5.8K]
3 years ago
15

Brenda’s scores on the first three of four 100-point science tests were 95, 92, and 89. What score does she need on her fourth s

cience test to ensure an average score of at least 93?. . A) X ≥ 96. B) X ≤ 90. C) X ≥ 88. D) X ≤ 92
Mathematics
2 answers:
attashe74 [19]3 years ago
6 0
Average of 93

4 scores
(95+92+89+x)/4<u>></u>93
times 4 both sides
276+x<u>></u>372
minus 276 both sides
x<u>></u>96


A
Marrrta [24]3 years ago
5 0
The average is equal to the mean of the data set. It is the total of the data or numbers given divided by the ordinal unit of the data set. In this case, we are given with scores of <span>95, 92, and 89. To have an average of at least 93, the fourth score should be : 
95 + 92 + 89 + x </span><span>≥ 93 * 4 where 4 is the number of data points. 
</span>x <span>≥ 96. Test score should be equal or greater than 96.</span>
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) Picture frames are produced such that the four sides of a picture frame consist of two pieces from a population whose mean len
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Answer:

The mean perimeter of frame = 38 cm

Step-by-step explanation:

By perimeter of a rectangle, the formula is given as:

Perimeter of rectangle = 2(A + B)

Going by the illustration in the question, the perimeter is

==> 2(32 + 44) = 152 cm.

However, we a given the mean perimeter of the frame which are:

32 and 44. We can either choose to say; each sides is (32 by 32) and (44 by 44). Or we consider it in mean/average term as given: (32 by 44).

Case 1: To obtain the mean perimeter of the frame using the first scenario, we say:

Mean perimeter = (32+32+44+44)/4 = 38 cm.

Case 2: We can simply say:

Mean perimeter = (32 + 44)/2 = 38 cm.

Graphically: Assuming that the frame is given below

                     32 cm

          ---------------------------------

         |                                      |

         |                                      |

44 cm|                                      | 44 cm

         |                                      |

         |                                      |

         |                                      |

         ----------------------------------

                       32 cm

The mean of upper frame/bars = 32 cm

The mean of side frame/bars  =  44 cm

Hence, the mean of the perimeter = (32 + 44)/2 = 38 cm

OR,

we take the sum of all the sides (32 + 44 + 32 + 44) and divide by total number of sides (4). That is;

The mean of the perimeter = (32 + 44 + 32 + 44)/4 = 38 cm

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