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seraphim [82]
2 years ago
6

URGE

Mathematics
1 answer:
lina2011 [118]2 years ago
7 0

Answer:

La probabilidad de que el estudiante entre, es 0.7

Entonces la probabilidad de que el estudiante no entre, es 1 - 0.7 = 0.3.

Ahora, si de 5 estudiantes, 3 entran y 2 no, entonces la probabilidad para un dado arreglo es: 0.7 tres veces, y 0.3 dos veces.

Y la probabilidad conjunta es igual al producto de las probabilidades individuales.

P = (0.7^3)(0.3^2)

Pero esto es para un arreglo, tenemos que tener en cuenta las permutaciones.

Sabemos que para M elementos, el numero de diferentes arreglos de N elementos (tal que N ≤ M) es:

C(M, N) = \frac{M!}{(M - N)!*N!}

En este caso, tenemos que M = 5 y N = 3, entonces tenemos:

C(5, 3) = \frac{5!}{2!*3!}  = 5*4/2 = 10

Entonces la probabilidad va a ser:

P = 10* (0.7^3)(0.3^2) = 0.3087

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