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1 answer:
Answer:
La probabilidad de que el estudiante entre, es 0.7
Entonces la probabilidad de que el estudiante no entre, es 1 - 0.7 = 0.3.
Ahora, si de 5 estudiantes, 3 entran y 2 no, entonces la probabilidad para un dado arreglo es: 0.7 tres veces, y 0.3 dos veces.
Y la probabilidad conjunta es igual al producto de las probabilidades individuales.
P = (0.7^3)(0.3^2)
Pero esto es para un arreglo, tenemos que tener en cuenta las permutaciones.
Sabemos que para M elementos, el numero de diferentes arreglos de N elementos (tal que N ≤ M) es:
En este caso, tenemos que M = 5 y N = 3, entonces tenemos:
Entonces la probabilidad va a ser:
P = 10* (0.7^3)(0.3^2) = 0.3087
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The probability that all three players obtain an odd sum is 3/14.
<h3>What is probability?</h3>The probability is the ratio of possible distributions to the total distributions.
I.e.,
Probability = (possible distributions)/(total distributions)
<h3>Calculation:</h3>Given that,
There are nine tiles - 1, 2, 3,...9, respectively.
A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.
In the given nine tiles the number of odd tiles = 5 and the number of even tiles = 4.
The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.
So,
One player can be selected in ways.
The 3 odd tiles out of 5 can be selected in ways.
The remaining 2 odd tiles can be selected and distributed in ways.
The remaining 4 even tiles can be equally distributed in ways.
So, the possible distributions = ×
×
×
⇒ 3 × 10 × 2 × 6 = 360
To find the total distributions,
The first player needs 3 tiles from the 9 tiles in ways
The second player needs 3 tiles from the remaining 6 tiles in ways
The third player takes the remaining tiles in 1 way.
So, the total distributions = 84 × 20 × 1 = 1680
Therefore, the required probability = (possible distributions)/(total distributions)
⇒ Probability = 360/1680 = 3/14.
So, the required probability for the three players to obtain an odd sum is 3/14.
Learn more about the probability of distributions here:
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