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charle [14.2K]
3 years ago
13

In a relay race, the probability of the Galaxy team winning is 22%. In another unrelated relay race, the probability of the Kome

ts team winning is 47%. If the possibility of a tie is not an option, the probability of the Komets losing their race and the Galaxy winning theirs is %.
Mathematics
2 answers:
steposvetlana [31]3 years ago
4 0
In probability, an "or" means adding the probabilities, and an "and" means multiplying them.
The probability of Komets losing is 100-47 = 53% = .53. The probability of the Galaxy winning is 22% = .22.
Therefore, the probability of Komet losing AND Galaxy winning is

.53 × .22 = .1166
11.66%
Shalnov [3]3 years ago
3 0

Answer: There is probability of approximately 12% that Komets losing their race and the Galaxy winning their game.

Explanation:

Since we have given that

Probability of the Galaxy team wins = 22%

Probability of the Komets team wins = 47%

So, Probability of the Komets losing their race is given by

100-47=53\%

We need to find the probability of the Komets losing their and the Galaxy winning their game .

Let Event K : Komets losing their game

Event G : Galaxy winning their game

Since these are two independent events,

So,

P(K\cap G)=P(K).P(G)\\\\P(K\cap G)=0.22\times 0.53\\\\P(K\cap G)=0.1166=0.12=12\%

So, there is probability of 12% that Komets losing their race and the Galaxy winning their game.


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What is the slope of у>- 2х + 3
charle [14.2K]

Answer:

-2x

Step-by-step explanation:

Graph

y > −2x + 3

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

y = mx + b

Find the values of m and b using the form y = mx + b. m = −2

b = 3

The slope of the line is the value of m, and the y-intercept is the value of b.

Slope: −2

intercept: (0, 3)

Graph a dashed line, then shade the area above the boundary line since y is greater than

−2x + 3.

y > −2x + 3

8 0
3 years ago
How many different 10 person committees can be selected from a pool of 23 people?
Salsk061 [2.6K]

We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.

We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.

Formula for combination:

C(n,r)=\dfrac{n!}{(n-r)!r!}

Where n represents the number of objects/people in the set and r represents the number of objects/people being chosen from the set

There are 23 people in the set and 10 people being chosen from the set

C(23,10)=\dfrac{23!}{(23-10)!10!}

=\dfrac{23!}{13!\times10!}

Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

=1,144,066

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!

~ Padoru

4 0
3 years ago
Read 2 more answers
if a square + b square + c square minus ab minus bc minus ca equals to zero, prove that A equals to B equal to C
lawyer [7]
A^2 + b^2 + c^2  - ab - bc - ca = 0
a.a + b.b + c.c = a.b + b.c + c.a

equating  term by term:- 
a = b
b = c 
c = a

Therefore a = b = c 
8 0
3 years ago
22. Solve for x.<br> 95°<br> +9<br> 24°
blondinia [14]

Answer:

I would say its 24 hope this helps

4 0
3 years ago
Select ALL the correct answers.
stiv31 [10]

Answer:

Statements 3, 4 and 5 are true.

Step-by-step explanation:

x^2 - 8x + 4

Using the quadratic formula:

x = [ -(-8) +/- √((-8)^2 - 4*1*4)] / 2

= (8 +/- √(64 - 16)) / 2

= 4 +/- √48 / 2

= 4 +/- 4√3/2

= 4 +/- 2√3.

So the third statement is true.

Converting to vertex form:

x^2 - 8x + 4

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= (x - 4)^2 -12

So the extreme value is at (4, -12)

So the fourth statement is true.

The coefficient of the term in x^2 is 1 (positive) so the graph has a minimum.

4 0
3 years ago
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